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Tcecarenko [31]
3 years ago
12

Find common 1/2 + 4/10 =

Mathematics
2 answers:
ratelena [41]3 years ago
6 0

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

                  Hello!

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

❖ 1/2 + 4/10 = 9/10

1       4         5 + 4       9

--  +  --  =    ---------  =  --

2      10         10          10

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

vitfil [10]3 years ago
4 0

[ Answer ]

\boxed{\frac{9}{10} }

[ Explanation ]

\frac{1}{2} + \frac{4}{10}

Find LCD Of 2 & 10: LCD Is 10

Rewrite Fractions Using LCD:

\frac{5}{10} + \frac{4}{10}

= \frac{9}{10}

\boxed{[ \ Eclipsed \ ]}

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If no two numbers are the same, then there's no mode. 
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Rob is on vacation in Paris France when rob visit the Eiffel tower today he climbed 1000 stairs and 25 minutes tomorrow rob will
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Answer:

It will take rob 7 minutes to climb the stairs tomorrow.

Step-by-step explanation:

1000/25=40

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What is 2 3/8 - 1 5/8 =
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19/8 - 13/8

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3 years ago
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The diagonals of parallelogram LMNO, LN and MO intersect at point P. If LP = 7, MP = 5x-10, and OP = 2x+2
fenix001 [56]
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7 0
4 years ago
The number of large cracks in a length of pavement along a certain street has a Poisson distribution with a mean of 1 crack per
Kipish [7]

Answer:

6.53% probability that there will be exactly 8 cracks in a 500 ft length of pavement

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Poisson distribution with a mean of 1 crack per 100 ft.

So \mu = \frac{ft}{100}, in which ft is the length of the pavement.

What is the probability that there will be exactly 8 cracks in a 500 ft length of pavement

500ft, so \mu = \frac{500}{100} = 5

This is P(X = 8).

P(X = 8) = \frac{e^{-5}*5^{8}}{(8)!} = 0.0653

6.53% probability that there will be exactly 8 cracks in a 500 ft length of pavement

8 0
3 years ago
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