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gogolik [260]
3 years ago
6

For which of the following sets of data should a stacked bar chart be used? A. The average height of men vs. the average height

of women B. The number of red cars vs. the number of red bicycles C. The total number of movies watched categorized by science fiction vs. non-science fiction D.The average age of surfers vs. the average age of scuba divers
Mathematics
1 answer:
Kobotan [32]3 years ago
8 0

Answer:

C. The total number of movies watched categorized by science fiction vs. non-science fiction

Step-by-step explanation:

A stacked bar chart is a type of graph that is mostly used to simplify multiple parts and compare them as a whole.

It uses different "bars" and each bar represents one part of the whole and segments of that bar show the different parts or categories of the whole.

Consider option A

In this option, the total average height of men and women cannot be considered as a whole. Therefore, the stacked chart cannot be used.

Consider option B

In this option, the totak number of red cars and bicycles cannot be considered as a whole because cars and bicycles are two different kinds of sets.

Consider option C

Here, the total number of movies watched categorized by science fiction and non-science fiction can be considered a whole because science and non-science fiction movies are the same sets of data and they add up to the total number of movies.

Hence, a stacked graph is appropriate here.

Option C is the correct answer

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Answer:

A) classify the value 1.2 as an outlier, because it is more than 1.5 × IQR below the first  quartile.

Correct we satisfy that 1.2 <1.7 the lower limit

Step-by-step explanation:

Assuming this complete question: A violin student records the number of hours she spends practicing during each of nine consecutive weeks:

6.2 5.0 4.3 7.4 5.8 7.2 8.4 1.2 6.3

For this case we need to sort the data first on increasing way and we got:

1.2, 4.3, 5.0, 5.8, 6.2, 6.3, 7.2, 7.4, 8.4

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The third quartile would be 7.2 since we analyze 6.2, 6.3, 7.2, 7.4, 8.4 and the middle point is 7.2

Then the interquartile rnage would be:

IQR = Q_3 -Q_1= 7.2-5=2.2

And 1.5 IQR = 1.5*2.2=3.3

The lower limit on this case would be:

LL= Q_1 -1.5 IQR= 5-3.3=1.7

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A) classify the value 1.2 as an outlier, because it is more than 1.5 × IQR below the first  quartile.

Correct we satisfy that 1.2 <1.7 the lower limit

B) not classify the value 1.2 as an outlier, because it is not more than 1.5 × IQR below  the first quartile.

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C) classify the value 1.2 as an outlier, because it is more than 1.5 × IQR below the  median.

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D) classify the value 1.2 as an outlier, because it is more than 1.5 × IQR below the  mean.

False we analyze if is an outlier comparing with the Q1 or Q3 not with the mean

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