Rational Because it can be simply as 3/1
<h2>The height of the rocket increases for some time and then decreases for some time.</h2>
The height from the ground increases from 4 to 26, then decreases from 26 to 0.
Why the others are wrong.
A. The height of the rocket changes at a constant rate for the entire time.
The graph is a curve. This means the rate is not constant. If it were constant, the graph would be linear - a straight line.
C. The height of the rocket remains constant for some time.
The graph is a curve. This means the rate is not constant. If it were constant, the graph would be linear - a straight line.
D. The height of the rocket decreases for some time and then increases for some time.
This implies the graph decreases first then increases. However, the rocket will increase, then decrease.
Answer:
38
Step-by-step explanation:
Replace all the variables with the given numbers:
(5)²+2(8)÷2(2)+3(3)
Multiply the numbers to get the final equation:
25+16÷4+9
Solve:
25+16÷4+9=38
Answer: 54.29%
Step-by-step explanation:
Given: The probability that they will win both games is 38%.
i.e. P( both games will win) =0.38
The probability that they will win just the first game is 70%.
P(first game will win) = 0.70
To find : P(second game will win| first game will win)
Using formula: 
So, P(second game will win| first game will win) = 
Hence, the required probability = 54.29%
Answer:
Total number of tables of first type = 23.
Total number of tables of second type = 7
Step-by-step explanation:
It is given that there are 30 tables in total and there are two types of tables.
Let's call the two seat tables, the first type as x and the second type as y.
∴ x + y = 30 ......(1)
Also a total number of 81 people are seated. Therefore, 2x number of people would be seated on the the first type and 5y on the second type. Hence the equation becomes:
2x + 5y = 81 .....(2)
To solve (1) & (2) Multiply (1) by 2 and subtract, we get:
y = 7
Substituting y = 7 in (1), we get x = 23.
∴ The number of tables of first kind = 23
The number of tables of second kind = 7
