Answer:
x=10 and W=12
Step-by-step explanation:
Let's solve the equations. First we need to understand that the problem can be solved because we have two variables (x, W) and two equations.
Now, we have the following equations:
3x+3W-66 making the equation equal to 0:
3x+3W-66=0 which can be express as:
3x=-3W+66
x=(-3W+66)/3
x=-W+22 (equation 1)
The next equation is:
12x+15W-300 making the equation equal to 0 and then divided by 3:
(12x+15W-300)/3=0 which is:
4x+5W-100=0 (equation 2), using equation 1 we can write:
4(-W+22)+5W-100=0
-4W+88+5W-100=0
W-12=0
W=12
Using W=12 in equation 2 we have:
4x+5W-100=0
4x+5*(12)-100=0
4x+(60)-100=0
4x-40=0
4x=40
x=40/4
x=10
In conclusion the solution for the equations are: x=10 and W=12.
Answer:
(2, 1)
Step-by-step explanation:
The solution is the point where the two lines intersect. In this case, that is (2, 1)
I think its fqalse sure thio
Answer/Step-by-step explanation:
1. Side CD and side DG meet at endpoint D to form <4. Therefore, the sides of <4 are:
Side CD and side DG.
2. Vertex of <2 is the endpoint at which two sides meet to form <2.
Vertex of <2 is D.
3. Another name for <3 is <EDG
4. <5 is less than 90°. Therefore, <5 can be classified as an acute angle.
5. <CDE is less than 180° but greater than 90°. Therefore, <CDE is classified as an obtuse angle.
6. m<5 = 42°
m<1 = 117°
m<CDF = ?
m<5 + m<1 = m<CDF (angle addition postulate)
42° + 117° = m<CDF (Substitution)
159° = m<CDF
m<CDF = 159°
7. m<3 = 73°
m<FDE = ?
m<FDG = right angle = 90°
m<3 + m<FDE = m<FDG (Angle addition postulate)
73° + m<FDE = 90° (Substitution)
73° + m<FDE - 73° = 90° - 73°
m<FDE = 17°
Answer:
a = -8
Step-by-step explanation:
19 = -3a - 5
Add 5 to both sides.
24 = -3a
Divide both sides by -3.
-8 = a
Switch sides.
a = -8
