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Vadim26 [7]
3 years ago
6

In a one-way ANOVA, what is the difference between the among-groups variance MSA and the within-groups variance MSW?

Mathematics
1 answer:
LuckyWell [14K]3 years ago
8 0

Answer:

MSR=MSA=\frac{SSR}{k-1}

And MSE=MSW=\frac{SSE}{N-k}

The difference is that MSA takes incount the variation between the groups and the grand mean, and the MSW takes in count the variation within groups respect to the mean of each group .

Step-by-step explanation:

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".  

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"  

If we assume that we have j groups and on each group from j=1,\dots,j we have n_j individuals on each group we can define the following formulas of variation:  

SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2  

SS_{between=Treatment}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2  

SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2  

And we have this property  

SST=SS_{between}+SS_{within}=6750+8000=14750  

The degrees of freedom for the numerator on this case is given by df_{num}=k-1 where k  represent the number of groups.  

The degrees of freedom for the denominator on this case is given by df_{den}=df_{between}=N-k.  

And the total degrees of freedom would be df=N-1  

We can find the MSR=MSA=\frac{SSR}{k-1}

And MSE=MSW=\frac{SSE}{N-k}

The difference is that MSA takes incount the variation between the groups and the grand mean, and the MSW takes in count the variation within groups respect to the mean of each group .

And the we can find the F statistic F=\frac{MSR}{MSE}=

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If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle?
kondaur [170]

Equation of the circle is (x+6)^{2}+(y+10)^{2}=20.

Solution:

The endpoints of the diameter of a circle are (–8, –6) and (–4, –14).

Center of the circle = Mid point of the diameter

Mid point formula:

$P(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)

Here, x_1=-8, y_1=-6, x_2=-4, y_2=-14

$P(x, y) =\left(\frac{-8-4}{2}, \frac{-6-14}{2}\right)

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$P(x, y) =(-6, -10)

Center of the circle = (–6, –10)

Radius is the distance between center and any endpoint of the diameter.

To calculate the radius using distance formula.

r=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}

Here, x_1=-6, y_1=-10, x_2=-8, y_2=-6

r=\sqrt{\left(-8-(-6)\right)^{2}+\left(-6-(-10)}\right)^{2}}

r=\sqrt{(-8+6)^{2}+(-6+10)^{2}}

r=\sqrt{(-2)^{2}+(4)^{2}}

r=\sqrt{20} units

The standard form of the equation of a circle is

(x-a)^{2}+(y-b)^{2}=r^{2}, where (a, b) are center and r is the radius.

Here, center = (–6, –10) and r=\sqrt{20}

(x-(-6))^{2}+(y-(-10))^{2}={(\sqrt{20})} ^{2}

(x+6)^{2}+(y+10)^{2}=20

Equation of the circle is (x+6)^{2}+(y+10)^{2}=20.

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The length of the time that randy read is 45 minutes.

<h3>What is time?</h3>

Time is known to be an element that is often measured or that is measurable.

From the image attached, Randy started reading at 4:10 and Randy finished reading at 4:55.

We therefore need to subtract:

4:55 - 4:10 = 45 minutes

So, Randy is said to read  for 45 minutes.

It is a period via which an action, process, etc. is alive or continues such as duration. One can tell the time by counting the minutes and seconds.

Learn more about time from

brainly.com/question/25607827

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