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Alekssandra [29.7K]
3 years ago
7

Powdered sodium carbonate reacts with a solution of sulphuric acid (H2SO4) to make a solution of sodium sulphate and water

Chemistry
1 answer:
Sphinxa [80]3 years ago
6 0

Answer:

yes

Explanation:

Na2CO3 + H2SO4 --> Na2SO4 + H2O + CO2

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In which of the following is the number of electrons the ion contains given correctly
larisa [96]

Answer:

B. K+ has 18 electrons

Explanation:

  • Ions are formed when atoms of element gain or loose electrons.
  • <em><u>When an atom looses electrons it forms a positively charged ion and when an atom gains electrons it forms a negatively charged ion.</u></em>
  • Metal atoms such as potassium, magnesium and aluminium looses outer most electrons to positively charged ions.
  • <u>Potassium atom has 19 electrons, 19 protons, with an electronic configuration of 2 : 8 : 8 : 1.</u> <u><em>To form an ion, K looses an electron to form a positively charged potassium ion (K+) with 18 electrons and 19 protons and an electronic configuration of 2:8:8.</em></u>
8 0
3 years ago
Calculate the number of C, H, and O atoms in 1.50 g of glucose, a sugar
DIA [1.3K]
Chemical formula of the glucose: C₆H₁₂O₆

We calculate the molar mass:
atomic mass (C)=12 u
atomic mass (H)=1 u
atomic mass (O)=16 u

atomic weight (C₆H₁₂O₆)=6(12 u)+12(1u)+6(16 u)=72 u+12u+96 u=180 u.
Therefore : 1 mol of glucose will be 180 g
The molar mass would be: 180 g/ mol


2) we calculate the number of moles of 1.5 g.
180 g---------------------1 mol
1.5 g----------------------  x

x=(1.5 g * 1 mol) / 180 g≈8.33*10⁻³ moles

we knows that:
1 mol = 6.022 * 10²³ particles (atoms or molecules)

3)We calculate the number of molecules:

Therefore:
1 mol-----------------------6.022*10²³ molecules of glucose
8.33*10⁻³ moles--------        x

x=(8.33*10⁻³ moles * 6.022*10²³ molecules)/1 mol≈5.0183*10²¹ molecules.

4)We calculate the number of C, H and O atoms:
A molecule of glucose have 6 atoms of C, 12 atoms of H, and 6 atoms of O,
number of atoms of C=(6 atoms/1 molecule)(5.0183*10²¹molecules)≈
3.011*10²²

number of atoms of H=(12 atoms/1 molecule)(5.0183*10²¹ molecules)≈
6.022*10²² .

number of atoms of O=(6 atoms/1 molecule)(5.0183*10²¹ molecules)≈
3.011*10²²

Answer: we have 3.011*10²² atoms of C, 6.022*10²² atoms of H, and 3.011*10²² atoms of O.
4 0
4 years ago
Need helpppp please
Vladimir79 [104]

Answer:

message me so i can help you because i cant see the words

Explanation:

6 0
3 years ago
Planck’s constant relates the joules of energy absorbed/released by matter to the ________. atomic number of the element frequen
mamaluj [8]

<span>Planck’s constant relates the joules of energy absorbed/released by matter to the wave frequency f. the plancks constant was first recognized in 1900 by Max Planck. The equation that relates the joules of energy absorbed/released by matter to the wave frequency f is called the plancks-eintein relation, E = hf</span>

5 0
3 years ago
Pentane is a small liquid hydrocarbon, between propane and gasoline in size at C5H12. The density of pentane is 0.626 g/mL and i
Goshia [24]

Answer : The fuel value and the fuel density of pentane is, 49.09 kJ/g and 3.073\times 10^4kJ/L respectively.

Explanation :

Fuel value : It is defined as the amount of energy released from the combustion of hydrocarbon fuels. The fuel value always in positive and in kilojoule per gram (kJ/g).

As we are given that:

\Delta H^o_{comb}=-3535kJ/mol

Fuel value = \frac{\Delta H^o_{comb}}{\text{Molar mass of pentane}}

Molar mass of pentane = 72 g/mol

Fuel value = \frac{3535kJ/mol}{72g/mol}

Fuel value = 49.09 kJ/g

Now we have to calculate the fuel density of pentane.

Fuel density = Fuel value × Density

Fuel density = (49.09 kJ/g) × (0.626g/mL)

Fuel density = 30.73 kJ/mL = 3.073\times 10^4kJ/L

Thus, the fuel density of pentane is 3.073\times 10^4kJ/L

4 0
4 years ago
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