The answer to this problem is quite simple, it’s 9
1) Chemical reaction
CH3 CH2 OH + O2 ---> CH3COOH + H2O
It is balanced
2) Molar ratios
1 mol CH3 CH2OH : 1 mol O2 : 1 mol CH3COOH : 1 mol H2O
3) Conversion of 7.6 grams of ethanol to moles
Molar mass of CH3CH2OH = 2 * 12g/mol + 6 * 1 g/mol + 16 g/mol = 46 g/mol
moles = mass / molar mass = 7.6 g / 46g/mol = 0.165 mol
4) Use of proportions with the molar ratios:
1mol CH3CH2OH / 1mol O2 = 0.165 mol CH3CH2OH / x => x = 0.165 mol CH3CH2OH.
5) Conversion of 0.165 mol O2 to grams
mass in grams = number of moles * molar mass = 0.165 mol * (2 * 16g/mol)
mass = 5.28 g ≈ 5.3 g
Answer: 5.3 g
Answer:

Explanation:
H₂O(ℓ) ⟶ H₂O(g)


Data:
T = 25 °C
ΔG° = 8.6 kJ·mol⁻¹
Calculations:
T = (25 + 273.15) K = 298.15 K

Standard pressure is 1 bar.

Methane, nitrogen, dark matter, and radiation.