What's 5/3x(-6/7) In simplest terms??

The formula for the area of a triangle is 1/2bh=A. Which of the following is not a possible first step to rearrange this formula

yarga [219]

We want to put b alone on one side of the equation.

If we multiply by 1/2, we get 1/4bh = A/2. Not only did we not remove a variable from the left side, we made it even more complicated.

So the answer is A.

7 0

3 years ago

Mid-West Publishing Company publishes college textbooks. The company operates an 800 telephone number whereby potential adopters

s344n2d4d5 [400]

The various answers to the question are:

To answer 90% of calls instantly, the organization needs four extension lines.
The average number of extension lines that will be busy is Four
For the existing phone system with two extension lines, 34.25 % of calls get a busy signal.

<h3>How many extension lines should be used if the company wants to handle 90% of the calls immediately?</h3>

a)

A number of extension lines needed to accommodate $90 in calls immediately:

Use the calculation for busy k servers.

$P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{k} \frac{\left(\frac{\lambda}{\mu}\right)^{t}}{i !}}$

The probability that 2 servers are busy:

The likelihood that 2 servers will be busy may be calculated using the formula below.

$P_{2}=\frac{\frac{\left(\frac{20}{12}\right)^{2}}{2 !}}{\sum_{i=0}^{2} \frac{\left(\frac{20}{12}\right)^{t}}{i !}}$$\approx 0.3425$$

Hence, two lines are insufficient.

The probability that 3 servers are busy:

Assuming 3 lines, the likelihood that 3 servers are busy may be calculated using the formula below.

$P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{2} \frac{\left(\frac{\lambda}{\mu}\right)^{i}}{i !}}$ \\\\$P_{3}=\frac{\frac{\left(\frac{20}{12}\right)^{3}}{3 !}}{\sum_{i=0}^{3} \frac{\left(\frac{20}{12}\right)^{1}}{i !}}$$\approx 0.1598$$

Thus, three lines are insufficient.

The probability that 4 servers are busy:

Assuming 4 lines, the likelihood that 4 of 4 servers are busy may be calculated using the formula below.

$P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{k} \frac{\left(\frac{\lambda}{\mu}\right)^{t}}{i !}}$ \\\\$P_{4}=\frac{\frac{\left(\frac{20}{12}\right)^{4}}{4 !}}{\sum_{i=0}^{4} \frac{\left(\frac{20}{12}\right)^{7}}{i !}}$$

Generally, the equation for is mathematically given as

To answer 90% of calls instantly, the organization needs four extension lines.

b)

The probability that a call will receive a busy signal if four extensions lines are used is,

$P_{4}=\frac{\left(\frac{20}{12}\right)^{4}}{\sum_{i=0}^{4} \frac{\left(\frac{20}{12}\right)^{1}}{i !}} $\approx 0.0624$$

Therefore, the average number of extension lines that will be busy is Four

c)

In conclusion, the Percentage of busy calls for a phone system with two extensions:

The likelihood that 2 servers will be busy may be calculated using the formula below.

$P_{j}=\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}$$\\\\$P_{2}=\frac{\left(\frac{20}{12}\right)^{2}}{\sum_{i=0}^{2 !} \frac{\left(\frac{20}{12}\right)^{t}}{i !}}$$\approx 0.3425$$

For the existing phone system with two extension lines, 34.25 % of calls get a busy signal.

Read more about signal

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3 0

1 year ago

How to slice using substitution method

marishachu [46]

Answer:

x=3, y=8; (3,8)

Step-by-step explanation:

To use the substitution method, first solve for a variable.

2x+y=14

2x+y(-2x)=14(-2x)

y=14-2x

Now substitute y in the other equation with 14-2x

5x-2(14-2x)= - 1

Simplify by multiplying inside the parenthesis.

5x-28+4x= - 1

Combine the x values

9x-28= - 1

9x=27

x=3

Now substitute the x value in to solve for y

2(3)+y=14

6+y=14

y=8

3 0

3 years ago

I need help, how do you do this

adell [148]

Answer: So you are going to make an equation first.

Step-by-step explanation:

first we know that for the first 2 hours the snow fell at an inch an hour. so we are going to make our first plots ( I suggest using an online site like geogebra or desmos to start out with before plotting for your assingment)

our first plot is going to be at (1,1) or 1 over and 1 up. remember points are in the form of (x,y). then (2,2)

Now we see that it has changed now there is no new snow for 6 hours so you are going to have a flat line so its going to be (2,2) then its going to continue that way as (3,2),(4,2), (5,2) (6,2)(7,2)(8,2).

It starts snowing again and now we have a new thing to plot the snow is falling at a constant of 3 inches an hour for the next 5 hours so now we are going to plot hte points to get our points we are going add 3 inches to our current inches each new hour. so its going to be (9,(2+3)) which is (9,5) and continue on doing that so we will have the plots (10,8) (11,11) (12,14) (13,17). and now we connect our plots by creating segments so then you do that on your thing and youre set to go I hope this helps.

6 0

2 years ago

Which number has the same value as 7 X 1/1000

Yuki888 [10]

Thw answer would be 0.007

5 0

3 years ago