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TEA [102]
2 years ago
14

The chromosomes in the nucleus of a cell contain a code known as_______.

Biology
2 answers:
erik [133]2 years ago
6 0

Answer:

D

Explanation:

Hope this helps

Have a great day

solniwko [45]2 years ago
4 0

Answer:

dna

Explanation:

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The main events in meiosis During the first division, chromosomes pair and sections of are exchanged between non-sister chromati
andrew11 [14]

Answer:

Cytokinesis divides the two cells into four daughter cells.

Explanation:

Meiosis is a type of cell division in which a single cell is divided into four daughter cells. These daughter cells are haploid i. e. half number of chromosomes. This type of cell division occurs only in sex cells of male and female organisms. There are two phases of meiosis. In meiosis 1, a single cell is divided into two daughter cells while in meiosis 2, these two daughter cells again divided into four daughter cells.

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Describe one model of the structure of a nucleus.
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Nucleus for what?

Atom? Animal Cell? Plant Cell? Each have different structures.
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Ram started his bussiness with cash re 500000 journilise the question​
marissa [1.9K]

Answer:

___________________________________

Date Particular L.F Debit Credit

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a. Cash a/c Dr. 500000

To capital a/c. 500000

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<h3>Some rules of Debit and credit:</h3>
  • Personal account

Personal account is related to proper noun like name of person, name of bank and company.

Rules for personal account:

Debit: the receiver

Credit: The giver

Personal Account is used to record credit transactions.

  • Real account

It is related to visible things except personal account terms.

For example: Goods, Cash, Furniture, Vehicles, Buildings.

Rules for Real Account:

Debit: What comes in

Credit: What goes out

  • Nominal Account

Nominal account refers to those things which cannot be seen but can be expressed in terms of money.For example: Rent, Salary, Wages, Commission, Tax etc.

Rules for Nominal Account:

Debit: All expenses and losses

Credit: All income and profit

Note: Every debit should have equal credit.

Hope this helps..

Good luck on your assignment...

3 0
3 years ago
What is an energy transformation?
Annette [7]
The conversion of one form of energy into another, or the movement of energy from one place to another. Solar panels allow for energy transfer from light energy to heat and electrical energy.
3 0
3 years ago
In a hypothetical population of 2500 people, 2275 people have brown eyes and 225 people have blue eyes (the homozygous-recessive
aev [14]

Answer:

In the next generation of 4000 children, 1680 of them will be heterozygous for the eye colour.

Explanation:

There's a population of 2500, 2275 of with have brown eyes and 225 blue eyes. <u>Let's call the dominant allele associated with brown colour "B" and the recessive allele associated with blue colour "b"</u>. So the possible genotypes are BB, Bb and bb, being BB and Bb brown eyed individuals and bb blue eyed individuals.

If the population it's in Hardy-Weinberg equilibrium, it means genotypic and allelic frequencies don't change from one generation to the following.

From the information given, we can calculate both allelic and genotypic frequencies.

First, we know that the frequency of the genotype bb it's the amount of blue eyed individuals over the total population.

  • f(bb)=225/2500=0.09

Additionally we know the allelic frequencies can be related to the genotypic ones when the population it's in Hardy-Weinberg equilibrium. Particularly we can say:

  • f(bb)=[f(b)]^2 => f(b)=[f(bb)]^(1/2)= 0.3 <em>(square root of f(bb)).</em>

Also, we can calculate the frequency of the B allele, as the probability of all alleles of the gene sum 1. In other words:

f(b)+f(B)=1 => f(B)=1 - f(b) = 1 - 0.3 = 0.7

So far, we have calculated the allelic frequencies, f(b)=0.3 and f(B)=0.7.

Now we can calculate the genotypic frequencies, using the equations of the Hardy-Weinberg equilibrium.

  • f(bb)=[f(b)]^2 => f(bb)=0.3^2=0.09
  • f(Bb)=2*f(B)*f(b) => f(Bb)=2*0.7*03=0.42
  • f(BB)=[f(B)]^2 => f(BB)=0.7^2=0.49

Finally, knowing that there are 4000 children in the next generation, to know how many of them are expected to be heterozygous for the eye colour, we should multiply the number of children for the probability of being heterozygous for the eye colour (which is the genotypic frequency for the genotype Bb).

  • Nº of heterozygous individuals = f(Bb)*total population= 0.42*4000
  • => Nº of heterozygous individuals =1680

<em />

3 0
3 years ago
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