Simple.....
you have this fraction...
simplify...
42/6=7
and
60/7=10
Thus...
Thus, she has saved
of the money.
Answer:
12 m/s²
Step-by-step explanation:
mass of the car = 50 kg
The net force applied to the car is 800 - 200 = 600 N
Form the Newton's second law:
F = m*a
where F is the net force applied to the object, m is the mass of the object, and a is the acceleration of the object.
Then, the acceleration of the car (in m/s²) is:
a = F/m
a = 600/50
a = 12 m/s²
Answer:
566 ft
Step-by-step explanation:
Given the polynomial equation
-16t² + 300t + 30 = 0
We're asked to find how high the rocket would rise in a 2 second fuse rise. This is a simple instruction that can be obtained by setting the unknown, t, in the equation to 2. Doing this, we have
-16 * 2² + 300 * 2 + 30
-16 * 4 + 600 + 30
-64 + 630 = 566 ft
Then, we can therefore conclude that the rocket will rise high up to a distance of 566 ft
Answer:
54 is th area
Step-by-step explanation:
i have a pitucre your welcome :)
When a perpendicular is dropped from the right-angle (C) to the opposite side AB, the metric relations apply:
BD*BA=a^2 ..........................(1)
AD*AB=b^2...........................(2)
BD*DA=DC^2........................(3)
Given AD=6, AB=24, using metric relation (2) above, we have
b^2=6*24=144
=>
b=sqrt(144)=12
By the way, we conclude that this is a 30-60-90 triangle because b/AB=(1/2)=sin(B) => B=30 degrees.
Answer: b=12
