Answer:
following are the solution to the given points:
Step-by-step explanation:
In point a:
calculating unit vector:
the point Q is at a distance h from P(6,6) Here, h=0.1
the value of Q= (5.92928 ,6.07071 )
In point b:
Calculating the directional derivative of at P in the direction of
In point C:
Computing the directional derivative using the partial derivatives of f.
Given :
A trailer will be used to transport several 40-pound crates to a store.
The greatest amount of weight that can be loaded into the trailer is 1,050 pounds.
An 82-pound crate has already been loaded onto the trailer.
To Find :
The greatest number of 40-pound crates that can be loaded onto the trailer.
Solution :
Weight left = 1050 - 80 = 970 pound.
Let, number of 40 pounds crates that can be loaded are x.
Since, crate cannot be in fraction, so maximum crate that can be loaded is 24.
Hence, this is the required solution.
Answer: (A) The image of JKL after a 90° counterclockwise about the origin is shown in figure 1. (B) The image of JKL after a reflection across the y-axis is shown in figure 2.
Explanation:
(A)
From the given figure it is noticed that the coordinate points are J(-4,1), K(-4,-2) and L(-3,-1).
If a shape rotate 90 degree counterclockwise about the origin, then,
Therefore, the vertex of imare are J'(-1,-4), K'(2,-4) and L'(1,-3). The graph is shown in figure (1).
(B)
If a figure reflect across the y-axis then,
Therefore, the vertex of imare are J''(4,1), K''(2,-4) and L''(3,-1). The graph is shown in figure (2).
