Answer:
-5/3 = m
Step-by-step explanation:
Don't you mean (4, -1) and (1, 4)? If so, if we start with (1, 4) and move to (4, -1), then x (the "run") increases by 3 and y (the "rise") decreases by 5. Then the slope is m = rise / run = -5/3 = m
Answer:
a) NORM.S.INV(0.975)
Step-by-step explanation:
1) Some definitions
The standard normal distribution is a particular case of the normal distribution. The parameters for this distribution are: the mean is zero and the standard deviation of one. The random variable for this distribution is called Z score or Z value.
NORM.S.INV Excel function "is used to find out or to calculate the inverse normal cumulative distribution for a given probability value"
The function returns the inverse of the standard normal cumulative distribution(a z value). Since uses the normal standard distribution by default the mean is zero and the standard deviation is one.
2) Solution for the problem
Based on this definition and analyzing the question :"Which of the following functions computes a value such that 2.5% of the area under the standard normal distribution lies in the upper tail defined by this value?".
We are looking for a Z value that accumulates 0.975 or 0.975% of the area on the left and by properties since the total area below the curve of any probability distribution is 1, then the area to the right of this value would be 0.025 or 2.5%.
So for this case the correct function to use is: NORM.S.INV(0.975)
And the result after use this function is 1.96. And we can check the answer if we look the picture attached.
we are given
now, we can factor out right side term
now, we can plug back
and we get
so,
.............Answer
Answer:
18m?
Step-by-step explanation:
Answer:
4/9
Step-by-step explanation:
The scale factor for the linear dimensions of the ball bearings will be the cube root of the volume scale factor:
k = ∛(1.6/5.4) = 2/3
Then the scale factor for the areas will be the square of this scale factor:
ratio of surface area = (2/3)² = 4/9
_____
The area is the product of two linear dimensions, so its scale factor is the product of the linear dimension scale factors. That is, the scale factor for area is the square of the linear dimension scale factor.
Similarly, volume is the product of three linear dimensions, so its scale factor is the cube of the linear dimension scale factor.