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2 years ago

90° 46° Find the unknown. angle measure please help :)

Mathematics

2 answers:

Yuki888 [10]2 years ago

6 0

=180-90-46
=34

Because it should be 180 all added up

Ganezh [65]2 years ago

5 0

Answer:

44 Give me brainliest please!

Step-by-step explanation:

180-90-46

90-46

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Find the measures of angels of M and N<br><br>M (6y-10)<br><br>N (4y-10)

PSYCHO15rus [73]

We have been given an image of a trapezoid. We are asked to find the measure of angle M and N.

We know that bases of trapezoid are parallel and the two angles between two parallel lines are supplementary, so we can set an equation as:

$\angle M+\angle N=180$

$(6y-10)+(4y-10)=180$

$6y-10+4y-10=180$

$10y-20=180$

$10y-20+20=180+20$

$10y=200$

$\frac{10y}{10}=\frac{200}{10}$

$y=20$

Upon substituting value of y in measure of angle M, we will get:

$m\angle M=6y-10$

$m\angle M=6(20)-10$

$m\angle M=120-10$

$m\angle M=110$

Therefore, measure of angle M is 110 degrees.

Similarly, we will find the value of angle N as:

$m\angle N=4y-10$

$m\angle N=4(20)-10$

$m\angle N=80-10$

$m\angle N=70$

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3 years ago

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Answer:

Step-by-step explanation:

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3 years ago

What is the value of x

pashok25 [27]

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Step-by-step explanation:

Generally, the algebraic expression should be any one of the forms such as addition, subtraction, multiplication and division. To find the value of x, bring the variable to the left side and bring all the remaining values to the right side. Simplify the values to find the result. Therefore, the value of x is -10.

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Answer:

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Step-by-step explanation:

For two matrix P and Q, the product, say PQ is defined when:

The number of columns of P = The number of rows of Q

Since A is a 2×2 matrix and B is also a 2×2 matrix

Thus both AB and BA are possible.

So AB is:

$AB\Rightarrow\begin{bmatrix}1 & 3\\ 2 & 1\end{bmatrix}\begin{bmatrix}3 & 6\\ -1 & 1\end{bmatrix}\\AB\Rightarrow\quad \begin{bmatrix}3\times 1+3\times (-1) & 6\times 1+3\times 1\\3\times 2+1\times (-1) & 6\times 2+1\times 1\end{bmatrix}\\AB\Rightarrow \quad \begin{bmatrix}0 & 9\\ 5 & 13\end{bmatrix}$

BA is:

$BA\Rightarrow\begin{bmatrix}3 & 6\\ -1 & 1\end{bmatrix}\begin{bmatrix}1 & 3\\ 2 & 1\end{bmatrix}\\BA\Rightarrow\quad \begin{bmatrix}3\times 1+6\times 2 & 3\times 3+6\times 1\\(-1)\times 1+1\times 2 & (-1)\times 3+1\times 1\end{bmatrix}\\BA\Rightarrow \quad \begin{bmatrix}15 & 15\\ 1 & -2\end{bmatrix}$

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