Which polynomial is in standard form
1 answer:
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Answer:
=
(3n + 7)
Step-by-step explanation:
We require to find the first term a₁ and the common difference d
The n th term is given by 3n + 2, thus
a₁ = 3(1) + 2 = 3 + 2 = 5
a₂ = 3(2) + 2 = 6 + 2 = 8
d = 8 - 5 = 3
=
[ 2a₁ + (n - 1)d ], substitute values
=
[ (2 × 5) + 3(n - 1) ] =
(10 + 3n - 3) =
(3n + 7)