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vova2212 [387]
2 years ago
5

Determine the intercepts of the line. X-intercept:(____,____) Y-intercept:(____,____)

Mathematics
1 answer:
Anastasy [175]2 years ago
7 0
X intercept is (-250,0) and y intercept is (0,100). Intercepts are where a line crosses the x axis and y axis.
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Does anyone know what to do on this by chance?
Anna [14]

Answer: The length is 45

Explanttio:

6 0
3 years ago
Read 2 more answers
How do I solve : COT pi/4 ...?
Wewaii [24]
Cot x = cos x / sin x
cot π/4 = cot 45° = cos 45° / sin 45°
We know that sin 45° and sin 45° have the same value:
cos 45° = sin 45° = √2 / 2;
cos 45° / sin 45° = √2/2 : √2/2 = 1
Answer:
cot π/4 = 1
3 0
3 years ago
What is the answer to 3 3/8 - 1 5/6=
Ilya [14]

Answer:

37/24

Step-by-step explanation:

3 0
2 years ago
JUST REPOSTING THIS QUESTION UNTIL I GET A CORRECT ANSWER lol!
yawa3891 [41]

Answer:

3x+(8x+15=180

3x+8x+15)=180

11x+15=180

11=180-15

11x=165

x=165/11

x=15

4 0
2 years ago
Evaluate the limit of sequence:
mr_godi [17]

Rationalize both the numerator and denominator. Given

\dfrac{\sqrt a-\sqrt b}{\sqrt c-\sqrt d}

we can rationalize it by introducing conjugates of the numerator and denominator:

\dfrac{\sqrt a-\sqrt b}{\sqrt c-\sqrt d} \cdot \dfrac{\sqrt a+\sqrt b}{\sqrt a+\sqrt b} \cdot \dfrac{\sqrt c+\sqrt d}{\sqrt c+\sqrt d} \\\\ = \dfrac{\left(\sqrt a\right)^2 - \left(\sqrt b\right)^2}{\left(\sqrt c\right)^2-\left(\sqrt d\right)^2} \cdot \dfrac{\sqrt c+\sqrt d}{\sqrt a + \sqrt b} \\\\ = \dfrac{a-b}{c-d} \cdot \dfrac{\sqrt c+\sqrt d}{\sqrt a + \sqrt b}

Then the limit is equivalent to

\displaystyle \lim_{n\to\infty} \frac{(n+3)-n}{(n+1)-n} \cdot \dfrac{\sqrt{n+1}+\sqrt n}{\sqrt{n+3}+\sqrt n} = 3 \lim_{n\to\infty} \dfrac{\sqrt{n+1}+\sqrt n}{\sqrt{n+3}+\sqrt n}

For the remaining expression, divide through uniformly by \sqrt n:

\dfrac{\sqrt{n+1}+\sqrt n}{\sqrt{n+3}+\sqrt n} = \dfrac{\sqrt{1+\frac1n} + 1}{\sqrt{1+\frac3n}+1}

As <em>n</em> goes to infinity, the remaining terms containing <em>n</em> converge to 0, leaving

\dfrac{\sqrt{1}+1}{\sqrt1+1} = \dfrac22 = 1

making the overall limit 3.

8 0
2 years ago
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