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3 years ago

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Find the surface area of the following figure below. Use 3.14 for pi

1 answer:

olasank [31]3 years ago

8 0

Question:

Find the surface area of the following figure below. Use 3.14 for pi

Answer:

9

Step-by-step explanation:

The circle has the same value of the side which is 3 so the length and width is 3 too. So the formal is L x W = Area. So this means 3 x 3 = 9

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Help me asap! I will give you marks

Law Incorporation [45]

Recall the binomial theorem.

$(a+b)^n = \displaystyle \sum_{k=0}^n \binom nk a^{n-k} b^k$

1. The binomial expansion of $\left(1+\frac x3\right)^7$ is

$\left(1 + \dfrac x3\right)^7 = \displaystyle\sum_{k=0}^7 \binom 7k 1^{7-k} \left(\frac x3\right)^k = \sum_{k=0}^7 \binom 7k \frac{x^k}{3^k}$

Observe that

$k = 1 \implies \dbinom 71 \left(\dfrac x3\right)^1 = \dfrac73 x$

$k = 2 \implies \dbinom 72 \left(\dfrac x3\right)^2 = \dfrac73 x^2$

When we multiply these by $8-9x$ ,

• $8$ and $\frac73 x^2$ combine to make $\frac{56}3 x^2$

• $-9x$ and $\frac73 x$ combine to make $-\frac{63}3 x^2 = -21x^2$

and the sum of these terms is

$\dfrac{56}3 x^2 - 21x^2 = \boxed{-\dfrac73 x^2}$

2. The binomial expansion is

$\left(2a - \dfrac b2\right)^8 = \displaystyle \sum_{k=0}^8 \binom 8k (2a)^{8-k} \left(-\frac b2\right)^k = \sum_{k=0}^8 \binom 8k 2^{8-2k} a^{8-k} b^k$

We get the $a^6b^2$ term when $k=2$ :

$k=2 \implies \dbinom 82 2^{8-2\cdot2} a^{8-2} b^2 = 28 \cdot2^4 a^6 b^2 = \boxed{448} \, a^6b^2$

6 0

1 year ago

What is the slope of a l8ne that contains the points (34,12) and (32,48)

Vlad [161]

I hope this helps you

slope (34-32)= 12-48

slope.2= -36

slope = -18

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3 years ago

Which is more? 1 gallon or 8 liters?

stiks02 [169]

Answer:

8 litres is roughly equivalent to 2 gallons, so 8 litres would be a lot more than 1 gallon. Hope this helps! :)

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3 years ago

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Is 70x8=490 pls answer

Anna71 [15]

Answer:

No

Step-by-step explanation:

70 * 8 = 560, not 490

Instead, 70 * 7 = 490

4 0

3 years ago

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Identify a and b in the binomial expression (2x3 + 3y2)7.

Shkiper50 [21]

$\text{Hey there!}$

$\text{Distribute the value of 7 in each of your terms}$

$\text{(2x}^3+\text{3y}^2)(7)$

$\text{2x}^3\times7=\text{14x}^3$

$\text{3y}^2\times7=\text{21y}^2$

$\text{We cannot combine like terms because they AREN'T any in this equation}$

$\boxed{\boxed{\bf{Answer:14x^3+21y^2}}}\checkmark$

$\text{Good luck on your assignment and enjoy your day!}$

~ $\frak{LoveYourselfFirst:)}$

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