Answer:$75.04
Step-by-step explanation:
last year price=$67
12% of 67
12/100 x 67
(12 x 67) ➗ 100
804 ➗ 100=8.04
Since it has risen by 12%
There new price is 67+8.04=75.04
Answer:
a) 0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b) 0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
Step-by-step explanation:
I am going to solve this question treating these events as Venn probabilities.
I am going to say that:
Event A: Person has type A blood.
Event B: Person has Rh- factor.
43% of people have type O blood
This means that 
15% of people have Rh- factor
This means that 
52% of people have type O or Rh- factor.
This means that 
a. Find the probability that a person has both type O blood and the Rh- factor.
This is

With what we have

0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b. Find the probability that a person does NOT have both type O blood and the Rh- factor.
1 - 0.06 = 0.94
0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
30 degrees due to the fact that all triangles interior angles add up to 180 degrees and there are two other angles meaning it is 30 degrees
Answer:
1 hot dog costs $0.75
1 bratwurst costs $1.35
Step-by-step explanation:
Let x and y be the price per dozen of hot dogs and bratwursts respectively.
The first day they sold 8 dozen hot dogs and 13 dozen bratwursts for $282.60
8x + 13y = 282.60
The second day they sold 10 dozen hot dogs and 15 dozen bratwursts for a total of $333.00
10x + 15y = 333
and we have the linear system
<em>8x + 13y = 282.60
</em>
<em>10x + 15y = 333
</em>
which can be written in matrix form as
The solution would be given by
We have
hence
Now,
if a dozen hot dogs cost $9, 1 hot dog costs 9/12 = $0.75
if a dozen bratwursts cost $16.2, 1 bratwurst costs 16.2/12 = $1.35
Answer:
It is the first graph
Step-by-step explanation:
You graph each point and it appears the same way