Given that Terry and Ed started a lawn mowing business and purchased the <span>the mowers and equipment for $1,300 which charged $15 for each lawn and use $2 worth of gas, the number of lawns that Terry and Ed must mow in order to break even would be 100 lawns. The answer would be option C. Hope this answer helps.</span>
The dice has 6 sides so out of 100% it would be 100/6=16.6666 so each side had a 16.6666% chance
h = 2

You must isolate the variable to solve using the order of operations, or PEMDAS.

Subtract 3 from both sides of the equation, and subtract 2h from both sides of the equation.

Divide both sides of the equation by 2.

Answer:
The mentioned number in the exercise is:
Step-by-step explanation:
To obtain the mentioned number in the exercise, first you must write the equations you can obtain with it.
If:
- x = hundredths digit
- y = tens digit
- z = ones digit
We can write:
- x = z + 1 (the hundreds digit is one more than the ones digit).
- y = 2x (the tens digit is twice the hundreds digit).
- x + y + z = 11 (the sum of the digits is 11).
Taking into account these data, we can use the third equation and replace it to obtain the number and the value of each digit:
- x + y + z = 11
- (z + 1) + y + z = 11 (remember x = z + 1)
- z + 1 + y + z = 11
- z + z +y + 1 = 11 (we just ordered the equation)
- 2z + y + 1 = 11 (z + z = 2z)
- 2z + y = 11 - 1 (we passed the +1 to the other side of the equality to subtract)
- 2z + y = 10
- 2z + (2x) = 10 (remember y = 2x)
- 2z + 2x = 10
- 2z + 2(z + 1) = 10 (x = z + 1 again)
- 2z + 2z + 2 = 10
- 4z + 2 = 10
- 4z = 10 - 2
- 4z = 8
- z = 8/4
- <u>z = 2</u>
Now, we know z (the ones digit) is 2, we can use the first equation to obtain the value of x:
- x = z + 1
- x = 2 + 1
- <u>x = 3</u>
And we'll use the second equation to obtain the value of y (the tens digit):
- y = 2x
- y = 2(3)
- <u>y = 6</u>
Organizing the digits, we obtain the number:
- Number = xyz
- <u>Number = 362</u>
As you can see, <em><u>the obtained number is 362</u></em>.
Answer:
Step-by-step explanation:
Arithmetic sequence
Tn = a+(n-1)d
= -85 +(601-1) 1/6
= -85 + 600/6
= -85 + 100
= 15
601th term is 15