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m_a_m_a [10]
3 years ago
15

. A businessman invested a total of Rs. 9,000 in two savings accounts. One account earns 8% interest per year and the other earn

s 10% interest per year. At the end of the first year, the two investments earned a total of Rs. 790 in interest. Find how much he invested on each accounts.
Mathematics
1 answer:
Alex17521 [72]3 years ago
3 0

Answer:

amount invested in the account that earns 10% interest  = Rs 3500

amount invested in the account that earns 8% interest  =Rs 5500

Step-by-step explanation:

Two equations can be derived from the question

x + y = 9000 equation 1

0.08x + 0.1y = 790 equation 2

x = amount invested in the account that earns 8% interest

y =  amount invested in the account that earns 10% interest

multiply equation 1 by 0.08

0.08x + 0.08y = 720 equation 3

subtract equation 3 from 2

0.02y = 70

divide both sides of the equation by 0.02

y = 70 / 0.02

y = 3500

Substitute for y in equation 1

x + 3500 = 9000

x = 9000 - 3500 = 5500

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Step-by-step explanation:

for 10, it doesn't really matter

8 0
3 years ago
Suppose a1={1,{2}}a1={1,{2}} and a2={∅,{1,2}}a2={∅,{1,2}} and a3={∅,{1},2}a3={∅,{1},2}. enter "t" for each true, and "f" for eac
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4 years ago
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guajiro [1.7K]
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4 years ago
For the following amount at the given interest rate compounded​ continuously, find​ (a) the future value after 9 ​years, (b) the
Stella [2.4K]

Answer:

(a) The future value after 9 ​years is $7142.49.

(b) The effective rate is r_E=4.759 \:{\%}.

(c) The time to reach ​$13,000 is 21.88 years.

Step-by-step explanation:

The definition of Continuous Compounding is

If a deposit of P dollars is invested at a rate of interest r compounded continuously for t years, the compound amount is

A=Pe^{rt}

(a) From the information given

P=4700

r=4.65\%=\frac{4.65}{100} =0.0465

t=9 \:years

Applying the above formula we get that

A=4700e^{0.0465\cdot 9}\\A=7142.49

The future value after 9 ​years is $7142.49.

(b) The effective rate is given by

r_E=e^r-1

Therefore,

r_E=e^{0.0465}-1=0.04759\\r_E=4.759 \:{\%}

(c) To find the time to reach ​$13,000, we must solve the equation

13000=4700e^{0.0465\cdot t}

4700e^{0.0465t}=13000\\\\\frac{4700e^{0.0465t}}{4700}=\frac{13000}{4700}\\\\e^{0.0465t}=\frac{130}{47}\\\\\ln \left(e^{0.0465t}\right)=\ln \left(\frac{130}{47}\right)\\\\0.0465t\ln \left(e\right)=\ln \left(\frac{130}{47}\right)\\\\0.0465t=\ln \left(\frac{130}{47}\right)\\\\t=\frac{\ln \left(\frac{130}{47}\right)}{0.0465}\approx21.88

3 0
3 years ago
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Vlada [557]
(x,y)
to be  a function
for every x, ther must be only 1 y to corespond to it
basically, x must NEVER repeat with a different y
list them

ah, we see (1,1) an d(1,-1)
also (4,2) and (4,-2)
double offense
1 repeats with 1 and -1
4 repeats with 2 and -2

not a function

domain is all x values
range is all y values
if they repeat, don't list them

domain=(0,1,4)
range=(-2,-1,0,1,2)
8 0
4 years ago
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