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2 years ago

Please help with this

Mathematics

1 answer:

agasfer [191]2 years ago

3 0

X = 180 degrees
That is. The answer

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Tell me what the slope and y intercept means to you

natka813 [3]

In the equation of a straight line (when the equation is written as "y = mx + b"), the slope is the number "m" that is multiplied on the x, and "b" is the y-intercept (that is, the point where the line crosses the vertical y-axis)

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2 years ago

Write the equation in standard form for the circle that has a diameter with endpoints (- 1, 12) and (- 1, 8)

matrenka [14]

Answer:

The equation in standard form is $(x + 1)^{2} + (y - 10)^{2} = 4$

Step-by-step explanation:

The distance from (-1, 12) to (-1, 8) = 4 = diameter of the circle. So, 2 = radius

The center of the circle is at (-1, 10)

The equation in standard form is $(x + 1)^{2} + (y - 10)^{2} = 4$

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2 years ago

If the discount is 27%, then what percentage of the original price do you pay? Please give an explanation as well if you can! Th

lina2011 [118]

100-27=73
Therefore you paid 73% of the original price. That’s the remaining percentage

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2 years ago

Given points A(-1, -2) and B(2, 4) where AP: BP=1:2, find the locus of point P.

koban [17]

Answer:

$x^2 + 4x + y^2 +8y = 0$

Step-by-step explanation:

Given

$A = (-1,-2)$

$B = (2,4)$

$AP:BP = 1 : 2$

Required

The locus of P

$AP:BP = 1 : 2$

Express as fraction

$\frac{AP}{BP} = \frac{1}{2}$

Cross multiply

$2AP = BP$

Calculate AP and BP using the following distance formula:

$d = \sqrt{(x - x_1)^2 + (y - y_1)^2}$

So, we have:

$2 * \sqrt{(x - -1)^2 + (y - -2)^2} = \sqrt{(x - 2)^2 + (y - 4)^2}$

$2 * \sqrt{(x +1)^2 + (y +2)^2} = \sqrt{(x - 2)^2 + (y - 4)^2}$

Take square of both sides

$4 * [(x +1)^2 + (y +2)^2] = (x - 2)^2 + (y - 4)^2$

Evaluate all squares

$4 * [x^2 + 2x + 1 + y^2 +4y + 4] = x^2 - 4x + 4 + y^2 - 8y + 16$

Collect and evaluate like terms

$4 * [x^2 + 2x + y^2 +4y + 5] = x^2 - 4x + y^2 - 8y + 20$

Open brackets

$4x^2 + 8x + 4y^2 +16y + 20 = x^2 - 4x + y^2 - 8y + 20$

Collect like terms

$4x^2 - x^2 + 8x + 4x + 4y^2 -y^2 +16y + 8y + 20 - 20 = 0$

$3x^2 + 12x + 3y^2 +24y = 0$

Divide through by 3

$x^2 + 4x + y^2 +8y = 0$

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2 years ago

I am greater than 310. My number has 0 ones.The digits in my hundreds and tens places are the same

mixas84 [53]

Step-by-step explanation:

Numbers: 330, 440, 550, 660 and so on all the way to 990

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2 years ago