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Basile [38]
3 years ago
7

I need help on this with solutions please

Mathematics
1 answer:
Zarrin [17]3 years ago
7 0

Answer:

<u>See answers below:</u>

  • 1. AAS
  • 2. ASA
  • 3. SAS
  • 4. HL
  • 5. SSS
  • 6. ΔABC ≅ ΔDFE
  • 7. ΔTRS ≅ ΔTUV
  • 8. ΔTRS ≅ ΔSUT
  • 9. ΔCAB ≅ ΔFDE

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The sum of the measures of angles for a triangle is 180°. Find the value of x and then the measures of the 3 angles
dmitriy555 [2]

Answer:

The value of x is 50

The measures of the 3 angles are 50°, 100°, 30°

Step-by-step explanation:

Let us solve the question

∵ The sum of the measures of the angles of a triangle is 180°

∵ The measures of the 3 angles of the given Δ are x°, 2x°, (x - 20)°

→ Add them and equate the sum by 180

∴ x° + 2x° + (x - 20)° = 180°

→ Add the like terms

∵ (x + 2x + x) + (-20) = 180

∴ 4x - 20 = 180

→ Add 20 to both sides

∵ 4x - 20 + 20 = 180 + 20

∴ 4x = 200

→ Divide both sides by 4 to find x

∴ x = 50

∴ The value of x is 50

To find the measures of the 3 angles substitute x by 50 in their expressions

∵ The measure of one angle is x

∴ The measure of the 1st angle is 50°

∵ The measure of the 2nd angle is 2x

∴ The measure of the 2nd angle = 2(50)

∴ The measure of the 2nd angle is 100°

∵ The measure of the 3rd angle is (x - 20)

∴ The measure of the 3rd angle = (50 - 20)

∴ The measure of the 3rd angle is 30°

∴ The measures of the 3 angles are 50°, 100°, 30°

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