“The breaking distance is directly proportional to the square of its speed”
Using your variables, this means: d = k•b^2
k here is some unknown (and for this question irrelevant) number.
Now if b (the speed) is increased by 200%, then your new speed is b+2b = 3b. The 2b is the 200% increase.
Throw 3b into the first equation we have the new d as:
d = k • (3b)^2
Simplifying this, you have d = k•9b or d=9kb
This means the new braking distance is 9 times the original braking distance.
The midpoint of that segment is (-8,-8).
9514 1404 393
Answer:
4mn/(3m+12)
Step-by-step explanation:
It is often helpful to factor expressions so that common factors can cancel.
Answer: Natural Numbers
Step-by-step explanation:
Okay so the equation. Lets say e is explorers and v is flying vs and m = money.
e + v > or = 30.
80e + 5v =m.
e < or = 20\
v < or = 20.
Okay, the most money he could make would be if he made 20 explorers at 80 dollars and 10 vs at 5 dollars.
Total money...
1600 + 50 = 1650.
So he could make $1650.
