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aniked [119]
3 years ago
15

1/5x+y=2/5 1/0x+1/3y=1/2

Mathematics
2 answers:
Nikolay [14]3 years ago
7 0
Best to enclose those fractions in parentheses:

(1/5)x + y = (2/5).

Otherwise, how would your reader know you didn't mean   1 / (5x) ?

Please note:  Your 1/0x involves division by zero and thus is not defined.  Make certain you've copied down the problem correctly.

If you present the following, instead, you can solve the system:

(1/5)x + y = (2/5).
       x + (1/3)y = (1/2)

Hint:  Determine what the LCD (lowest common denominator) is.  Multiply both equations by this LCD, to remove all fractions from the problem.


kkurt [141]3 years ago
4 0
A) 
<span>|x + y = 5 </span>
<span>|2x - y = 7; </span>
<span>b) </span>
<span>|2x + y = 5 </span>
<span>|x - y = 2 </span>
<span>c) </span>
<span>|3x + y = 6 </span>
<span>|4x - 3y = -5 </span>
<span>d) </span>
<span>|1/(x - 1) = y - 3 </span>
<span>|x - y = -2 </span>
<span>e) </span>
<span>|(9x + 4y)/3 - (5x - 11)/2 = 13 - y </span>
<span>|13x - 7y = -8 </span>
<span>Answer: </span>c<span> and </span>e<span> has solution (1; 3)</span>
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