Reflection means to flip across the axis. so A is ii.
x,y to x,-y means it stays on the x axis its on an negative y axis so B is iv.
translation means to slide so c is iii.
last one is i.
Answer:
6
Step-by-step explanation:
The ratio of
is a constant
=
=
= 
That is y =
x
When x = 21, then
y =
× 21 = 6
Step-by-step explanation:
4 administrator are eligible and the student relations committee has only 2 administrator there are C (4,2) ways of choosing the administrators for the student relations committee
similarly for faculty members ways (8,3) and for students C (20,5)
the number of possible committee = 4!/2!2! × 8!/3!5! ×20!/5!15!
= 6 ×56 ×15504
= 5,209,344
<h3>
Answer: B) 6</h3>
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Explanation:
x = original side length
2x = double the side length
The old area is x^2. The new square area is (2x)^2 = 4x^2
new area = (old area) + 27
4x^2 = x^2 + 27
4x^2-x^2 = 27
3x^2 = 27
x^2 = 27/3
x^2 = 9
x = sqrt(9)
x = 3
The old original square has a side length of 3 units.
The new larger square has a side length of 2x = 2*3 = 6 units which is the final answer (choice B)
old area = 3^2 = 9
new area = 6^2 = 36
The jump from 9 to 36 is +27 to help confirm the answer.
Answer:

Step-by-step explanation:
First find the <em>rate of change</em> [<em>slope</em>]:


Then plug these coordinates into the Slope-Intercept Formula instead of the <em>Point-Slope Formula</em> because you get it done much swiftly. It does not matter which ordered pair you choose:
15 = −1⅕[−10] + b
12

If you want it in <em>Standard Form</em>:
y = −1⅕x + 3
+1⅕x + 1⅕x
______________
[We do not want fractions in our Standard Equation, so multiply by the denominator to get rid of it.]
5[1⅕x + y = 3]

_______________________________________________
−3 = −1⅕[5] + b
−6

y = −1⅕x + 3
+1⅕x + 1⅕x
______________
[We do not want fractions in our Standard Equation, so multiply by the denominator to get rid of it.]
5[1⅕x + y = 3]

** You see? I told you it did not matter which ordered pair you choose because you will always get the exact same result.
I am joyous to assist you anytime.