0 because the number in the middle is the midpoint.
Im not sure what you are asking, but for a probability tree, you have the total # of something at the very top of the tree, next it branches out into groups, and those groups represent something like colored marbles or something... and to find percent you divide the total number like the number of marbles bye 100 and multiply that number bye the thing that you're trying to get job percent like a color of marbles, I hope this helped...
b ≤ 9 (b is less than or equal to 9)
Hope this helps! ;)
Answer:
The probably genotype of individual #4 if 'Aa' and individual #6 is 'aa'.
Step-by-step explanation:
In a non sex-linked, dominant trait where both parents carry and show the trait and produce children that both have and don't have the trait, they would each have a genotype of 'Aa' which would produce a likelihood of 75% of children that carry the dominant traint and 25% that don't. Since the child of #1 and #2, #5, does not exhibit the trait, nor does the significant other (#6), then they both must have the 'aa' genotype. However, since #4 displays the dominant trait received from the parents, it is more likely they would have the 'Aa' genotype as by the punnet square of 'Aa' x 'Aa', 50% of their children would have the 'Aa' phenotype.
