MCE = 360 - (150 + 70 + 50)
mCE = 360 - 270
mCE = 90
<CDE = 1/2(mBE + mCE)
<CDE = 1/2(150 + 90)
<CDE = 1/2(240)
<CDE = 120
answer
<CDE = 120°
The answer you're looking for is A
Answer:
(2x - 5y)²
(2x - 5y)(2x - 5y)
2x(2x - 5y) - 5y(2x - 5y)
2x(2x) - 2x(5y) - 5y(2x) + 5y(5y)
4x² - 10xy - 10xy + 25y²
4x² - 20y + 25y²
The answer is B.
Step-by-step explanation:
Answer:
111°
Step-by-step explanation:
Let the centre of the circle be C
mRQ=157 (marked)
The angle at the centre of a circle standing on an arc is twice any angle at the circumference, standing on the same arc. So <SCR=2(SQR)=2(46)=92. mSR=<SCR=92
All the arc measure add up to 360 so:
mSQ+mRQ+mSR=360
mSQ+157+92=360
mSQ=360-249=111
