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torisob [31]
2 years ago
7

Will someone please help me..?

Mathematics
1 answer:
bekas [8.4K]2 years ago
5 0

Answer:

What help do you need?

tell me about it

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What is 4 whols and 4/5 divided by 4/5
Delicious77 [7]

Answer:

6

Step-by-step explanation:

24/5 / 4/5

24/5 / 5/4

24/4 is 6

5/5 is 1

hope this helps:)

6

7 0
2 years ago
Write the equations of two lines that are parallel to the line 3x+6y-5=0
Alja [10]

Answer:

X+2Y=7 and 4X+8Y=19

Step-by-step explanation:

Step 1: Write the equations in the form y=mx+c, where m represents the gradient.

In this case, gradient is equal to -0.5

Step 2: Now fix arbitrary values on the equation, y=mx+c while maintaining the value of m as - 0.5

You can make endless equations

5 0
3 years ago
(3x^2 - 2x)(2x^2 + 3x - 1) Polynomials
dedylja [7]

Answer:

Step-by-step explanation:

3 0
3 years ago
Find the area of each regular polygon. Round your answer to the nearest tenth if necessary.
tatuchka [14]

*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*

(21)

Area of a Regular Hexagon: \frac{3\sqrt{3}}{2}(side)^{2} = \frac{3\sqrt{3}}{2}*(\frac{20\sqrt{3} }{3} )^{2} =200\sqrt{3} square units

(22)

Similar to (21)

Area = 216\sqrt{3} square units

(23)

For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:

altitude=\frac{\sqrt{3}}{2}*side

side = \frac{36}{\sqrt{3}}

Hence, area of the hexagon will be: 648\sqrt{3} square units

(24)

Given is the inradius of an equilateral triangle.

Inradius = \frac{\sqrt{3}}{6}*side

Substituting the value of inradius and calculating the length of the side of the equilateral triangle:

Side = 16 units

Area of equilateral triangle = \frac{\sqrt{3}}{4}*(side)^{2} = \frac{\sqrt{3}}{4}*256 = 64\sqrt{3} square units

4 0
3 years ago
Find the measurements of the numbered angles in each isosceles trapezoid.
SSSSS [86.1K]

Answer:

∠1 = 96°

∠2 = 84°

∠3 = 84°

Step-by-step explanation:

∠1 = 96°

∠2 = ∠3

∠1 + 96 + ∠2 + ∠3 = 360°

∠2 = (360 - 96 - 96)/2 = 84°

∠3 = 84°

8 0
3 years ago
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