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Advocard [28]
3 years ago
9

What is the area of a sector with a central angle of 210 degrees and a diameter of 4.6m?

Mathematics
1 answer:
WINSTONCH [101]3 years ago
8 0
Sector area = (central angle / 360) * PI * radius^2
sector area = (210 / 360) * PI * 2.3^2
sector area = (7 / 12) * PI * 5.29
<span><span><span>sector area = 9.6944313302 </span> </span> </span>
<span>sector area = 9.7 square meters (rounded)

Source:
http://www.1728.org/radians.htm

</span>
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I believe it should be 1.296 miles
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The smallest number that must be added to 1300 to make it a perfect cube is
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d. 31.

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3 0
2 years ago
1948 Olympics
mash [69]

Answer:

For 1948 Men's :Interquartile range is 1.5, Median is 58.3

For 2012 Men's: Interquartile range is 0.315, Median is 47.86

You can infer that in 2012 the swimmers were better and it was more competitive as the interquartile range was lower and the median was also lower as well

Step-by-step explanation:

1948 Men's 100m

57.3, 57.8, 58.1, 58.3, 58.3, 59.3, 59.6,1:00.5

               ⬆                ⬆                 ⬆

         Low IQR      Median       High IQR

Low IQR is average of 57.8 and 58.1 = 57.95

High IQR  is average of 59.3 and 59.6 =  59.45

Median is average of 58.3 and 58.3 = 58.3

Interquartile range is High IQR- Low IQR

59.45 - 57.95=1.5

2012 Men's 100m

47.52, 47.53, 47.8, 47.84, 47.88, 47.92, 48.04, 48.44

                    ⬆                  ⬆                      ⬆

             Low IQR         Median          High IQR

Low IQR is average of 47.53 and 47.8 = 47.665

High IQR is average of 48.04 and 47.92 = 47.98

Median is average of 47.88 and 47.84 = 47.86

Interquartile range is High IQR-Low IQR

47.98-47.665=0.315

Read more on Brainly.com - brainly.com/question/14915771#readmore

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3 years ago
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Here is the equations in standard form

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3 years ago
PLEASE HELP FIRST ANSWER IS THE BRAINLIEST ANSWER!!!
motikmotik

Step-by-step explanation:

There are no choices available, so here is a graph of that equation.  Simply compare it to the answer.

6 0
3 years ago
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