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3 years ago

13

380 KS3 students 240 KS4 students 110 KS5 students pick out 100 from all them combined estimate how many KS3 students there will

be

1 answer:

Leokris [45]3 years ago

7 0

Answer: 52

Step-by-step explanation:

KS3 students = 380

KS4 students = 240

KS5 students = 110

Total number of students = 730

Estimated number of KS3 students will be:

= 380/730 × 100.

= 52.06

= 52.

There'll be 52 KS3 students

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A food store makes a 11–pound mixture of peanuts, almonds, and raisins. The cost of peanuts is $1.50 per pound, almonds cost $3.

Anastaziya [24]

Answer:

C) 6 lbs peanuts, 3 lbs almonds, 2 lbs raisins

Step-by-step explanation:

Your goal is to find out how many of each item will equate to 21 dollars. Your function is as follows:

1.5x+3y+1.5z=21

Where x, y, z are peanuts, almonds, raisins respectively (in that order). 21 is the total cost of the mixture.

All you have to do is start plugging in the variables given in the answer choices.

<u>A) Peanuts (x) = 3, Almonds (y) = 6, Raisins (z) = 2</u>

Everywhere you see x,y,z, you replace with their value.

$1.5x+3y+1.5z=21\\1.5(3)+3(6)+1.5(2)=21\\4.5+12+3=21\\\\19.5 \neq 21$

A doesn't equal 21. On to the next one.

<u>B) Peanuts (x) = 8, Almonds (y) = 6, Raisins (z) = 2</u>

Everywhere you see x,y,z, you replace with their value.

$1.5x+3y+1.5z=21\\1.5(8)+3(1)+1.5(2)=21\\12+3+3=21\\\\18 \neq 21$

B also doesn't equal 21. On to the next one...

<u>C) Peanuts (x) = 6, Almonds (y) = 3, Raisins (z) = 2</u>

Everywhere you see x,y,z you replace with their value.

$1.5x+3y+1.5z=21\\1.5(6)+3(3)+1.5(2)=21\\9+9+3=21\\\\\\21 = 21$

Both sides of the equation equal 21 which means C is our answer.

7 0

3 years ago

Pls send help if i get it right you get brainliest

Goshia [24]

I think the top right 1 is linear

Top left is neither and bottom is exponential

6 0

3 years ago

Read 2 more answers

3p + 4r = q solve for p

Aleksandr-060686 [28]

Answer:

$p = \dfrac{q - 4r}{3}$

Step-by-step explanation:

3p + 4r = q

3p = q - 4r

$p = \dfrac{q - 4r}{3}$

7 0

4 years ago

Read 2 more answers

21 Last year Chelsea and Sonya took 236 pictures during Thanksgiving. This year Chelsea and Sonya each took the same amount of p

Leokris [45]

Let 'c' represent the number of pictures Chelsea took.

Let 's' represent the number of pictures Sonya took.

For last year's Thanksgiving, c + s = 236

For this year's Thanksgiving, let 'x' represent the number of photos taken in total. x = c + s, where c and s are two integers that are the same (c = s).

And we know that for both years, c + s + x = 500.

As we know that c + s is already 236 from last year, we can remove c + s from the equation in bold and replace it with 236 instead.

236 + x = 500.

Now we have to isolate the x term.

x = 500 - 236

x = 264.

We know that x = c + s, where c and s are the same, so we can just use one of the variables and double it (so you either get 2c or 2s - it doesn't matter which one you pick because they're both the same).

2c = 264

c = 132

c = s

s = 132.

Both took 132 pictures this year.

4 0

3 years ago

A) Find the distance of line segment PR. Round answer to the nearest tenth. B) Find the distance around the park (perimeter).

juin [17]

Answer:

A. $PR = 80.6 yd$

B. Perimeter = 190.6 yd

Step-by-step explanation:

A. Distance between P(10, 50) and R(80, 10):

$PR = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$PR = \sqrt{(80 - 10)^2 + (10 - 50)^2}$

$PR = \sqrt{(70)^2 + (-40)^2}$

$PR = \sqrt{4,900 + 1,600}$

$PR = \sqrt{6,500}$

$PR = 80.6 yd$ (nearest tenth)

B. Distance around the park = Perimeter = PR + PQ + QR

PR = 80.6 yd

PQ = |50 - 10| = 40 yd

QR = |80 - 10| = 70 yd

Perimeter = 80.6 + 40 + 70

Perimeter = 190.6 yd

7 0

3 years ago