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1 year ago

HELP!! is {(-3,-6),(-2,-1),(-1,-0),(0,3),(1,15)} a function??

Mathematics

1 answer:

Goshia [24]1 year ago

7 0

<h3>Answer: Yes it's a function</h3>

It's a function because we don't have any repeated x coordinates. Any given x input value leads to exactly one y output value.

The domain is {-3,-2,-1,0,1} which is the set of all x inputs.

The range is {-6, -1, 0, 3, 15} which is the set of y outputs.

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What is 15% of "x" PLEASE HELP

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2 years ago

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The curved surface area of a right circular cylinder of height 14 cm is 88 cm².

Slav-nsk [51]

Answer:

The diameter of the base of the cylinder is 2 cm.

Step-by-step explanation:

GIVEN :

As per given question we have provided that :

➣ Height of cylinder = 14 cm
➣ Curved surface area = 88 cm²

$\begin{gathered}\end{gathered}$

TO FIND :

in the provided question we need to find :

➠ Radius of cylinder
➠ Diameter of cylinder

$\begin{gathered}\end{gathered}$

USING FORMULAS :

$\star{\underline{\boxed{\sf{\purple{Csa = 2 \pi rh}}}}}$

$\star{\underline{\boxed{\sf{\purple{d = 2r}}}}}$

➛ Csa = Curved surface area
➛ π = 22/7
➛ r = radius
➛ h = height
➛ d = diameter

$\begin{gathered}\end{gathered}$

SOLUTION :

Firstly, finding the radius of cylinder by substituting the values in the formula :

$\begin{gathered} \qquad{\longrightarrow{\sf{Csa = 2 \pi rh}}} \\ \\ \qquad{\longrightarrow{\sf{88 = 2 \times \dfrac{22}{7} \times r \times 14}}} \\ \\ \qquad{\longrightarrow{\sf{88 =\dfrac{44}{7} \times r \times 14}}} \\ \\ \qquad{\longrightarrow{\sf{88 =\dfrac{44}{\cancel{7}}\times r \times \cancel{ 14}}}} \\ \\ \qquad{\longrightarrow{\sf{88 =44 \times r \times 2}}} \\ \\ \qquad{\longrightarrow{\sf{88 =88 \times r}}} \\ \\ \qquad{\longrightarrow{\sf{r = \frac{88}{88}}}} \\ \\ \qquad{\longrightarrow{\underline{\underline{\sf{\pink{r = 1 \: cm}}}}}} \end{gathered}$

Hence, the radius of cylinder is 1 cm.

———————————————————————

Now, finding the diameter of cylinder by substituting the values in the formula :

$\begin{gathered} \qquad{\longrightarrow{\sf{d = 2r}}} \\ \\ \qquad{\longrightarrow{\sf{d = 2 \times 1}}} \\ \\ \qquad{\longrightarrow{\underline{\underline{\sf{\red{r = 2 \: cm}}}}}}\end{gathered}$

Hence, the diameter of the base of the cylinder is 2 cm.

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