4) Let A = {7, 8, 9, 10, 11, 12), B = {9, 11, 13), C = {7, 8, 10, 12), D = {7, 12), and U = {7, 8, 9, 10, 11, 12, 13). 4) Вас A)
Elenna [48]
It is true as A consist {7,8,9,10,11,12} and B consists of{9,11,13} and C consist of {7,8,10,12} and D has{7,12} there are the set of numbers from 7 to 13 only so the answer is true that U={7,8,9,10,11,12,13}.
Answer:
(a)
Step-by-step explanation:
Given
See attachment for sets A and B
Required
The true statement about both sets
First, we calculate the typical values (mean) of set A and set B.
This is calculated as:
For A:
For B:
<em>Here, we can conclude that B has a larger typical value</em>
Next calculate the spread (range) of sets A and B
This is calculated as:
For A:
For B
<em>Here, we can conclude that A has a larger spread.</em>
<em></em>
<em>Hence, (a) is true</em>
Answer:
True.
Step-by-step explanation:
The left side of a "two column proof" is used for your "work" and the right side justifies your statements and is your "proof."
Find the area of the triangle shaped faces. The area of a triangle is b•h/2
7•2=14/2=7
then multiply it by 4.5,
the area is 31.5 in^2
$52,000 + 6% = $55,120
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