The number of stamps with penny in terms of x is 
<em><u>Solution:</u></em>
Given that,
Ryan has x stamps in his collection
Number of stamps of Ryan = x stamps
Let the stamps with penny be "a"
Ryan has 6 times as many stamps as penny
Therefore,
Number of stamps in Ryan = 6 times as many stamps as penny

Thus number of stamps with penny in terms of x is 
5x - 9.
Five times a number indicates multiplication and less than indicates subtraction. A number would be a variable since it isn’t specified.
Answer:
Q = (4, - 1)
Step-by-step explanation:
DF is the diameter of the circle with center Q.
So, Q is the midpoint of DF.
By mid point formula.

A
This is like a base form of a prime polynomial
X^2+x+1
Answer : 96
x – y = 16 --------> equation 1
1/8 x + 1/2 y = 52
x is the higher grade and y is the lower grade
We solve the first equation for y
x - y = 16
-y = 16 -x ( divide each term by -1)
y = -16 + x
Now substitute y in second equation
1/8 x + 1/2 ( -16 + x ) = 52
1/8x - 8 + 1/2 x = 52
1/8x + 1/2x - 8 = 52
Take common denominator to combine fractions
1/8x + 4/8x -8 = 52
5/8x - 8 = 52
Add 8 on both sides
5/8x = 60
Multiply both sides by 8/5
x = 96
We know x is the higher grade
96 is the higher grade of Jose’s two tests.