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Shalnov [3]
3 years ago
13

Jeremy can stand on one leg for 3.8 minutes. Express that time in seconds.

Mathematics
2 answers:
ICE Princess25 [194]3 years ago
8 0
1 min = 60sec
So just multiply your 3.8 by 60
Answer is 228
Salsk061 [2.6K]3 years ago
7 0

Answer:

He can stand on one leg for 228 seconds.

Step-by-step explanation:

You multiply the 3.8 seconds by 60.

So, 3.8 * 60 = 228

Hope this helps :)

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Identify the percent increase in total sales and the percent increase in sales of trench coats. Then find which percent of
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Answer:

Answer b: Sales of trench coats increased 8.3 percentage points faster than total coat sales.

Step-by-step explanation:

First add all the sales for 2006, and do the same for the 2007 sales, so we can compare both total sales numbers:

For 2006 we have:

103+297+210+213+137 = 960 total sales

For 2007 we have:

127+223+210+285+259 =  1104 total sales

The percent increase is calculated as the difference between the final value minus the original value, divided by the original value and multiplied by 100:

For the total number of coats we have that the percent increase is: \frac{1104-960}{960} * 100= 15%

For the trench coats (which went from 103 sales tp 127 sales) we have the following percent increase: \frac{127-103}{103} * 100= 23.3%

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23.3 % - 15% = 8.3%

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3 years ago
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Determine whether the source given below has the potential to create a bias in a statistical study. Washington University obtain
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Answer:

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Step-by-step explanation:

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3 years ago
John runs to the market and comes back in 15 minutes. His speed on the way to the market is 5m/s and his speed on the way back i
katen-ka-za [31]

Answer:

The distance to the market is 2000 m

Step-by-step explanation:

∵ John runs to the market and comes back in 15 minutes

→ Change the min. to the sec. because the unit of his speed is m/s

∵ 1 minute = 60 seconds

∴ 15 minutes = 15 × 60 = 900 seconds

→ Assume that t1 is his time to the market and t2 is his time from

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∵  t1 + t2 = 15 minutes

∴ t1 + t2 = 900 ⇒ (1)

→ Assume that the distance to the market is d

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∵ Time = Distance ÷ Speed

∴ t1 = d ÷ 5 ⇒ (1 ÷ 5 = 0.2)

∴ t1 = 0.2d ⇒ (2)

∵ His speed on the way back is 4m/s

∴ t2 = d ÷ 4 ⇒ (1 ÷ 4 = 0.25)

∴ t2 = 0.25d ⇒ (3)

→ Substitute (2) and (3) in (1)

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→ Divide both sides by 0.45

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