Answer:

Step-by-step explanation:
Given:
A car starts with a dull tank of gas
1/7 of the gas has been used around the city.
With the rest of the gas in the car, the car can travel to and from Ottawa three times.
Question asked:
What fractions of a tank of gas does each complete trip to Ottawa use?
Solution:
Fuel used around the city = 
Remaining fuel after driving around the city = 1 -
= 
According to question:
As from the rest of the gas in the car that is
, the car can complete 3 trip to Ottawa which means,
By unitary method:
The car can complete 3 trip by using =
tank of gas.
The car can complete 1 trip by using = 
=
= 
=
tank of gas
Thus,
tank of gas used for each complete trip to Ottawa.
Here is the formula you'll need
Total = Principal * (1 + (rate/n))^n*years
I don't know how to solve that for "n" so we'll use trial and error.
If compounded annually, total =
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10,841.24
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</span>
If compounded quarterly, total =
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<span>
10,955.64
</span>
</span></span><span>If compounded monthly, total =
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10,981.82
</span>
</span>
</span>
If compounded daily, total =
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<span>
10,994.58
</span>
</span>
</span>
Therefore the answer is "A", daily.
Source:
http://www.1728.org/compint3.htm
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Length of the room is 5 m and width is 5 + 2 = 7 m.
Hope this helps.
r3t40
If 1.5cm = 4ft
1.5÷4 =0.375
0.375cm= 1ft
16×0.375=6
12×0.375=4.5
hopefully this is correct and helped! ♡