Answer:
A
Step-by-step explanation:
Answer:
The 99% confidence interval estimate of the percentage of girls born is (86.04%, 93.96%). Considering the actual percentage of girls born is close to 50%, the percentage increased considerably with this method, which means that it appears effective.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of
.
In the study 380 babies were born, and 342 of them were girls.
This means that
99% confidence level
So
, z is the value of Z that has a p-value of
, so
.
The lower limit of this interval is:
The upper limit of this interval is:

As percentages:
0.8604*100% = 86.04%.
0.9396*100% = 93.96%.
The 99% confidence interval estimate of the percentage of girls born is (86.04%, 93.96%). Considering the actual percentage of girls born is close to 50%, the percentage increased considerably with this method, which means that it appears effective.
Answer:
<h2>
d = (4 x 180) - (3 x 90) = 450</h2>
Step-by-step explanation:
d = (4×180) - (3×90)
d = (720) - (270)
d = 720 - 270
d = 450
HOPE THIS HELPS YOU
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Answer:
a.) .0469
b.) .9961
c.) .9492
Rounded these check below for full answers
Step-by-step explanation:
a.)

b.)
Porbability of at most 3 successes is equal to 1-p(4)
p(4)=

1-.003690625=.99609375
c.)
two or more failures is equa lto
p(0)+p(1)+p(2)=
