Answer: The fraction of set of twins=![\frac{5}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B8%7D)
The fraction of sets of triplets=![\frac{2}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B8%7D)
The fraction of set of quadruplets=![\frac{1}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B8%7D)
Step-by-step explanation:
Given: The number of set of twins=5
The number sets of triplets = 2
The number of set of quadruplets=1
⇒ The total number of multiple birth students =5+2+1=8
∴ The fraction of set of twins=![\frac{\text{set of twins}}{\text{ total multiple birth students}}=\frac{5}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7Bset%20of%20twins%7D%7D%7B%5Ctext%7B%20total%20multiple%20birth%20students%7D%7D%3D%5Cfrac%7B5%7D%7B8%7D)
∴ The fraction of sets of triplets=![\frac{\text{set of triplets}}{\text{ total multiple birth students}}=\frac{2}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7Bset%20of%20%20triplets%7D%7D%7B%5Ctext%7B%20total%20multiple%20birth%20students%7D%7D%3D%5Cfrac%7B2%7D%7B8%7D)
∴ The fraction of set of quadruplets=![\frac{\text{set of quadruplets}}{\text{ total multiple birth students}}=\frac{1}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7Bset%20of%20quadruplets%7D%7D%7B%5Ctext%7B%20total%20multiple%20birth%20students%7D%7D%3D%5Cfrac%7B1%7D%7B8%7D)
Answer:
Step-by-step explanation:
ok so
4(x - 1) = – 4 + 4x
4x-4 = -4+4x
so Any value of ( x ) makes the equation true.
All numbers are a solution
You add 4 on both sides so the 4 cancels out and you know have 23+4= 27
D=27
Answer:
At least $141
Step-by-step explanation:
175-34=141