Answer:
The function that models the scenario is given as follows;

Step-by-step explanation:
The table of values are presented as follows;
The number of days, t, since the rumor started: 0, 1, 2, 3, 4, 5
The number of people, P, hearing the rumor: 10, 16, 26, 42, 66, 100
Imputing the given functions from the options into Microsoft Excel, and




solving using the given values of the variable, t, we have;
P t A B
C D
10
0
10
10
10
10
16
1
16.07021 16.27604 16.34583
16.38095
26
2
25.43466 26.2797 26.574 26.72363
42
3
39.33834 41.89929 42.82868 43.30901
66
4
58.85058 65.51853 68.09014 69.45316
100
5
84.17395 99.55866 106.0177 109.5721
Therefore, by comparison, the function represented by
most accurately models the scenario.