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2 years ago

8

The graph below point A represents Ashley's house point B represents Bridget's house and point C is Chloe's house. each unit on

the graph is 2 miles.
to the nearest tenth how many miles is ashleys house from bridgets house.?

1 answer:

abruzzese [7]2 years ago

4 0

Answer:

i dont know

Step-by-step explanation:

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F(x)= 2lxl? (graphing absolute values) I'm a little confused.

Vesnalui [34]

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Graph Transformation Rule:

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Read 2 more answers

I need only 16 and 17 please help

Nesterboy [21]

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Answer:

16. a: (-90°, (4, 3)); b: (90°, (0, 3)); c: (-90°, (0, 0))

17. a: (down, (4, -1)); b: (right, (4, 3)); c: (up, (5, 2))

Step-by-step explanation:

We don't know what notation you're used to seeing for rotations. Here. we'll use the form [degrees CCW, (center)]. (CW angles are negative.) In any rotation, the center is the point that is invariant (remains in the same place)

16.

a) The tail is invariant, so the rotation is (-90°, (4, 3)).

b) The tip is invariant, so the rotation is (90°, (0, 3)).

c) The origin is invariant, so the rotation is (-90°, (0, 0))

__

17.

a) The tail is invariant, so the arrow is pointing down with the tip at (4, -1).

b) The center is invariant, so the arrow is reversed. It is pointing right with the tip at (4, 3).

c) Point (2, 3) is invariant, so the arrow is pointing up with the center at (5, 0). The tip is at (5, 2).

_____

<em>Additional comment</em>

If you have trouble visualizing these rotations, you might find it useful to trace the arrow on a piece of (semi-)transparent medium (plastic or tracing paper) so that you can move it as required to match the descriptions in the problem statement. A pin, or a dot on your tracing, can serve to fix the center of rotation. A little hands-on never hurts in math and geometry.

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2 years ago

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2 years ago

A rare form of malignant tumor occurs in 11 children in a million, so its probability is 0.000011. Four cases of this tumor occ

Shkiper50 [21]

Answer:

a) The mean number of cases is 0.14608 cases.

b) The probability that the number of cases is exactly 0 or 1 is 0.990.

c) The probability of more than one case is 0.010

d) No, because the probability of more than one case is very small

Step-by-step explanation:

We can model this problem with a Poisson distribution, with parameter:

$\lambda=r*t=0.000011*13,280=0.14608$

a) The mean amount of cases is equal to the parameter λ=0.14608.

b) The probability of having 0 or 1 cases is:

$P(k=0)=\frac{\lambda^0 e^{-\lambda}}{0!}=\frac{1*0.864}{1} =0.864\\\\ P(k=1)=\frac{\lambda^1 e^{-\lambda}}{0!}=\frac{0.14608*0.864}{1} =0.126\\\\P(k\leq1)=0.864+0.126=0.990$

c) The probability of more than one case is:

$P(k>1)=1-P(k\leq 1)=1-0.990=0.010$

d) The cluster of 4 cases can not be due to pure chance, as it is a very high proportion of cases according to the average rate. Just having more than one case has a probability of 1%.

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2 years ago