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sladkih [1.3K]
2 years ago
5

Answer quick please!

Mathematics
2 answers:
8_murik_8 [283]2 years ago
8 0

Answer:

y = x/2 + 5

Step-by-step explanation:

y = x/2 + 5

⇒ y = (1/2)x + 5

which satisfies the linear equation y = mx + b

where m is the slope and b is the y-intercept

eimsori [14]2 years ago
7 0
Answer is B hope I helped!
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The options are: 3/10, 65%, 3/7, 70%
den301095 [7]

Answer:

70%

Step-by-step explanation:

there are 20 total marbles and only 14 are not blue so 14/20 = 7/10 = 70%

4 0
3 years ago
If the bisector of ST intersects at point N, and ST is 8in., what is NT? 4in., 12in., 16in., or 6in.
AnnyKZ [126]
2n and 10 n 2468101214n 16
8 0
4 years ago
NEED HELP ASAP WITHIN 10 MINUETS MY ASSIGNMENT IS DO PLEASE HELP!
Anna [14]

Answer: I do not have expertise on this so I won't answer the exact problem but this sounds like exponential decay, where you have the decay rate. I know that the formula for exponential decay is: y = a(1 - r)^x

I'm sorry if this does not help much I don't have expertise on this. Sorry again.

Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
What is x? 6x-18+14x+38
evablogger [386]

Answer:

x= -1

Step-by-step explanation:

6x-18+14x+38

group= 20x+20

set equal to 0

20x+20=0

       -20  -20

20x/20= -20/20

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8 0
3 years ago
Capital Value Suppose income from an investment starts (at time 0) at $6000 a year and increases linearly and continuously at a
nikdorinn [45]

The capital value$6507.63

Step-by-step explanation:

When an amount is compounded continuously interest it means the principal is continuously earning interest and the interest keeps earning on the interest earned. The formula to apply is;

A=Pe^{rt}

where P is the starting amount, r is the nominal annual interest rate, t is length of time the interest is applied, and e=2.71828

Given that, A=$6000, e=2.71828, r=0.05 and t=1

A=6000*2.71828^{0.05}

A=6307.63

Interest earned= 6307.63-6000 = $307.63

Where the investment increases linearly and at a constant rate of $200 a per , the linear model will be;

A=6000+200t where t is length of time the interest is applied, and A is the amount after t period of time

In this case t=1

A=6000+200*1

A=6000+200 =6200

Interest earned is= $6200-$6000=$200

Capital value = $6000+$307.63+$200 =$6507.63

Learn More

Interest compounded continuously:brainly.com/question/13009340

Keywords : capital value, investment, increases linearly, continuously rate

#LearnwithBrainly

7 0
3 years ago
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