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Keith_Richards [23]
3 years ago
6

Start with a circle whose equation is (x-a)^2

Mathematics
1 answer:
Nat2105 [25]3 years ago
5 0

Answer:

some circles are similar to a circle with a radius unit of 1

Step-by-step explanation:

(x-a)²

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Which is the next step in the following construction of a square?
Sedbober [7]

Answer:

(B)Place compass at point A, and open compass to greater than P.

Step-by-step explanation:

The following steps will be followed in the construction of a Square inscribed in a circle.

  • Draw a circle and label the center P.
  • Draw the diameter of the circle, labeling the endpoints A and B.
  • Construct the perpendicular bisector of the diameter, AB.
  • Label the points where the bisector intersects the circle as C and D.
  • Connect points A to B to C to D to form the square.

Now to construct a perpendicular bisector of AB, the next step is to place the compass at A and open the compass to greater than the center P of the circle. We do the same at point B.

The correct option is B.

7 0
3 years ago
Read 2 more answers
Nikita knows the following information about her food club that has 11 members: 3 members like neither fruit nor vegetables. 4 m
nataly862011 [7]

Answer:

Question was not fully given but...

Step-by-step explanation:

If you restate the full question it can be answered

4 0
4 years ago
Find the resultant force
Assoli18 [71]

951 1404 393

Answer:

  61.03 N at 35° above the horizontal

Step-by-step explanation:

The forces operate at right angles, so the Pythagorean theorem can be used to find the magnitude of the resultant:

  ||F1 +F2|| = √(50² +35²) = √3725 ≈ 61.03 . . . . newtons

The angle (α) relative to F2 can be found using the tangent relation.

  tan(α) = 50/35

  α = arctan(50/35) ≈ 55.008°

Then the angle relative to the horizontal reference line is ...

  55.0° -20° = 35.0°

The resultant is about 61.03 N at an angle of 35° above the horizontal.

5 0
3 years ago
Write the percent as a decimal. 122%​
muminat

Answer:

1.22

its obvious, lets say 100% of 1 is 1. 22% of 1 is 0.22. 1+0.22=1.22

6 0
4 years ago
Read 2 more answers
Write an equation for an ellipse centered at the origin, which has foci at (0,\pm\sqrt{63})(0,± 63 ​ )left parenthesis, 0, comma
steposvetlana [31]

Answer:

\frac{x^{2} }{4312 } + \frac{y^{2} }{8281 }

Step-by-step explanation:

Since the foci are at(0,±c) = (0,±63) and vertices (0,±a) = (0,±91), the major axis is the y- axis. So, we have the equation in the form (with center at the origin) \frac{x^{2} }{b^{2} } + \frac{y^{2} }{a^{2} }.

We find the co-vertices b from b = ±√(a² - c²) where a = 91 and c = 63

b = ±√(a² - c²)

= ±√(91² - 63²)

= ±√(8281 - 3969)

= ±√4312

= ±14√22

So the equation is

\frac{x^{2} }{(14\sqrt{22}) ^{2} } + \frac{y^{2} }{91^{2} } = \frac{x^{2} }{4312 } + \frac{y^{2} }{8281 }

8 0
4 years ago
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