Did I do this right? If not please explain!

Mathematics

1 answer:

andrew11 [14]2 years ago

5 0

Yep! Good job, you did it correctly.
Your y-intercept is equal to the constant of the equation (y-int = -2). Your movement/direction (or rise over run) is equal to the variable. Since your variable is x (which can also be written as 1x) means you move up one and over one (rise over run). This is because 1/1 is equal to 1.

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I am having trouble doing this problem

Norma-Jean [14]

Answer:

Step-by-step explanation:

A. when you multiply exponents with a common base you keep the base and add the exponents. In this case you would keep the 6 and add the -5 and 2 so the answer would be:

6^-3 which is not equivalent

B. You can distribute the exponent in to the parenthesis.

(1^5)/(6^2)^5

when you have an exponent to an exponent you mutliply. so the answer would be:

1^5/6^10

1^5 is always going to be 1 so you actually have:

1/6^10

when the exponent is on the bottom you can bring it to the top by making it negative, so the final answer for B is:

6^-10 which is equivalent

C. Same rules as B, multiply an exponent to an exponent.

6^(-5*2) = 6^-10 which is equivalent

D. When you are dividing exponents with a common base you subtract the top and bottom exponents. So in this case you have:

6^(-3-7) = 6^-10 which is equivalent

E. Using the rules from eariler the numerator can be simplified by adding the exponents.

6^5 * 6^-3 = 6^(5-3) = 6^2

which leaves you with:

6^2/6^-8

From there you can either bring the 6^-8 to the numberator to make it positive which simplifies to:

6^2 * 6^8 = 6^(2+8) = 6^10 which is not equivalent

or you can subtract the top and bottom exponents:

6^2/6^-8 = 6^(2-(-8))

the double negative cancels to a positive and you getL

6^(2+8) = 6^10 which is not equivalent

so B, C, and D are equal to 6^-10

6 0

3 years ago

The function g(x) undergoes a vertical stretch of 2, a horizontal shift to the right 3 units, and a vertical shift up 1 to becom

Maksim231197 [3]

Answer:

NONE OF THE OPTIONS GIVEN

Step-by-step explanation:

F(x) = 2|x - 3| + 1 is close, but vertical bars in stead of parentheses completely changes the curve shape

I believe it should be f(x) = 2(x - 3) + 1

if g(x) = x

here are some plots to compare the possibilities. I've shifted the vertical of each to separate the blue and green lines slightly. If they were both true "1" values the lines would be colinear for x>3.

The red line has a slope of 1, stretching by a factor of 3 means the slope is now 3. The absolute value signs from the answer options makes f(x) have a sharp V shape whereas the parentheses creates a single line for all values of x as does g(x) = x.