The form f(x) = a(bx) equals a. The initial value of the function f(x) = a(bx) is always a. This is due to the fact that an is not reliant on x. As a result, if x changes, bx will change as well, but a will not.
Note: √a * √a = a
√a * √b = √ab
(√2 + √10)² = (√2 + √10)(√2 + √10)
= √2(√2 + √10) + √10(√2 + √10)
= √2*√2 + √2*√10 + √10*√2 + √10*√10
= 2 + √20 + √20 + 10
= (2 + 10) + (√20 + √20)
= 12 + 2√20
√20 = √(4 *5) = √4 * √5 = 2√5
= 12 + 2√20 = 12 + 2(2√5)
= 12 + 4√5
<span>P - 3 1/6 = -2 1/2
3 1/6- 21/2
p=2/3 </span>
The solution to the problem is as follows:
<span>
cot θ = cos θ / sin θ </span>
<span>So sinθ * cot θ = cos θ after cancelling sin θ </span>
<span>Now cosθ + sin θ cot θ = cos θ + cos θ = 2 cos θ
</span>
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