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Fed [463]
3 years ago
8

7(3d + 12) if d=4 I don't know the answer please help.

Mathematics
1 answer:
Anastaziya [24]3 years ago
8 0

Answer:

Its 21+84

Step-by-step explanation:

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I have 56 apples and my horse at 12 apples. How many apples do I have left for my other horse?
timofeeve [1]

Answer:

44

Step-by-step explanation:

56 - 12= 44

7 0
3 years ago
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Find the value of m and b for the equation 0=-9x+5y+25
lukranit [14]

Answer:

X= -5

Y=-2.7

Step-by-step explanation:

YOU DO THIS BY SUBTRACTING 25 ON THE RIGHT SIDE TO THE LEFT ONLY LEAVING YOU WITH VARIABLES.

THEN YOU SUBSTITUTE ZERO INTO Y TO FIND X THEN SUBTITUTE ZERO INTO X TO FIND Y

BTW SUBSTITUTE ONE INTO THE VARIABLE YOU ARE FINDING

8 0
3 years ago
Which is another way to check the sum of 104+34+228+877?
Alex787 [66]
The answer is digit sum method.

Digit sum method is method used to check the sum of sum numbers. If the sum of all of the digits of numbers is equal to the sum of all of the digits of the total sum, then the arithmetic process was correct.

We need to check the sum of <span>104+34+228+877:
</span>104 + 34 + 228 + 877 = 1243

Let's first summarize the digits of individual numbers:
104 *** 1 + 0 + 4 = 5
34 *** 3 + 4 = 7
228 *** 2 + 2 + 8 = 12 *** 1 + 2 = 3
877 *** 8 + 7 + 7 = 22 *** 2 + 2 = 4

Now, let's sum these sums:
5 + 7 + 3 + 4 = 19 *** 1 + 9 = 10 *** 1 + 0 = <u><em>1</em></u>

Then, let's summarize the digits of the total sum:
1243 *** 1 + 2 + 4 + 3 = 10 *** 1 + 0 = <u><em>1</em></u>

Since the sums of the digits on the both sides of equation is 1, than the arithmetic process was correct and the sum of <span>104 + 34 + 228 + 877 is really 1243.</span>

7 0
3 years ago
Estimate the quotient by rounding the expression to relate to a one-digit fact. Explain your thinking in the space below. 432 ÷
blsea [12.9K]

Answer:

5.9..... there are a bunch of numbers after that but you would round it to 6.0

Step-by-step explanation:

6 0
3 years ago
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4)^-5 write in a simplified fraction
erastova [34]
\bf 4^{-5}?\qquad \textit{well, bear in mind that}\\&#10;----------------------------\\&#10;a^{-{ n}} \implies \cfrac{1}{a^{ n}}\qquad \qquad&#10;&#10;\cfrac{1}{a^{ n}}\implies a^{-{ n}}&#10;\\ \quad \\&#10;%  negative exponential denominator&#10;a^{{ n}} \implies \cfrac{1}{a^{- n}}&#10;\qquad \qquad &#10;&#10;\cfrac{1}{a^{- n}}\implies \cfrac{1}{\frac{1}{a^{ n}}}\implies a^{{ n}}\\&#10;----------------------------\\&#10;thus\implies 4^{-5}\implies \cfrac{1}{4^{+5}}\implies \cfrac{1}{4^5}\implies \cfrac{1}{1024}
8 0
3 years ago
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