If you are having trouble with ratios you can look at them as fractions. The first number being the numerator and the second number being the denominator or the other way around. When you are asked to find an equivalent ratio, you just have to find an equivalent fraction.
Q1
Answer:
![x \leqslant \frac{5}{3}](https://tex.z-dn.net/?f=x%20%5Cleqslant%20%20%5Cfrac%7B5%7D%7B3%7D%20)
Step-by-step explanation:
![3x \leqslant 5 \\ 3x \div 3 \leqslant 5 \div 3\\ x \leqslant \frac{5}{3}](https://tex.z-dn.net/?f=3x%20%5Cleqslant%205%20%5C%5C%203x%20%5Cdiv%203%20%5Cleqslant%205%20%5Cdiv%203%5C%5C%20x%20%5Cleqslant%20%20%5Cfrac%7B5%7D%7B3%7D%20)
explanation for second step:
you divide each side by 3 to get rid of the '3' in '3x'
Answer:
WXYZ can not be a rectangle because consecutive sides are not perpendicular to each other.
Step-by-step explanation:
The given vertices are W(-4,3), X(1,5), Y(3,1) and Z(-2,-1).
Plot these points on coordinate plane and draw the quadrilateral as shown below.
Using this formula, we get
Now,
Here, WX and XY are two consecutive sides of quadrilateral but the product of their slopes is not equal to -1. It means they are not perpendicular to each other.
Since, all interior angles of a rectangle are right angles, therefore, WXYZ can not be a rectangle.
Don’t know the answer I jus need to answer so I can ask another question