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Charra [1.4K]
3 years ago
9

74/360 in simplest form​

Mathematics
1 answer:
Umnica [9.8K]3 years ago
8 0

Answer:

37/180

Step-by-step explanation:

Reduce this fraction by dividing both sides by 2.  We get 37/180, which cannot be reduced further; 37 and 180 have no common factor.

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How much did Gloria make per hour if she worked 6 hours for for 2 days and made 114.24
Anna35 [415]

9.52 per hour for 6 hours 2 days. there is a total of 12 hours in total so divide 114.24 by 12 to get 9.52.

5 0
2 years ago
In the data set below, what is the mean absolute deviation?
MA_775_DIABLO [31]

here are the steps

1. you would take all the numbers and add them and u would get 18.

2. you want to then divide by 5 since that is how many numbers there are

3. your answer is then 3.6

4 0
2 years ago
Read 2 more answers
Steps to solve 5[3(14.5+7)-3]-7.4
steposvetlana [31]
Hey there!

To solve this expression, you must follow your orders of operations or PEMDAS (Parenthesis, Exponents, Multiplication and Division, Addition and Subtraction).

In the case of  <span>5[3(14.5+7)-3]-7.4, you not only have parenthesis, but you also have brackets. To start, you would first simplify what is in the parenthesis:
</span><span>5[3(14.5+7)-3]-7.4
5[3(21.5)-3]-7.4

Now, simplify what is in the bracket, starting by multiplying 3(21.5) since multiplication comes before addition and subtraction:
</span><span>5[3(21.5)-3]-7.4
5[64.5-3]-7.4
5[61.5]-7.4

Now, multiply 5*61.5 since multiplication comes next:</span>
<span>5[61.5]-7.4
307.5-7.4

And finally, subtract what is left since it is your final operation remaining to get 300.1 as your final answer.

Hope this helps and have a marvelous day!
</span>
6 0
3 years ago
Find the number of positive integers less than 100,000 whose digits are among 1, 2, 3, and 4. Hint consider the
Verdich [7]

Answer:

<em>1364</em> is the number of possibilities for positive integers less than 1,00,000.

Step-by-step explanation:

<em>1. 5 digit numbers:</em>

We have 5 places here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 5 digit numbers:

4 \times 4 \times 4 \times 4 \times 4\\ \Rightarrow 1024

<em>2. 4 digit numbers:</em>

We have 4 places here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 4 digit numbers:

4 \times 4 \times 4 \times 4 \\ \Rightarrow 256

<em>3. 3 digit numbers:</em>

We have 3 places here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 3 digit numbers:

4 \times 4 \times 4 \\ \Rightarrow 64

<em>4. 2 digit numbers:</em>

We have <em>2</em> places here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 2 digit numbers:

4 \times 4 \\ \Rightarrow 16

<em>5. 1 digit numbers:</em>

We have 1 place here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 1 digit numbers:

4

We can add all the above possibilities to find the total.

So,  number of positive integers less than 100,000 whose digits are among 1, 2, 3, and 4 = 1024 + 256 + 64 + 16 + 4 = <em>1364</em>

3 0
2 years ago
PV = nRT<br><br> Solve the formula for the BOLD variable. Bold variable is T
irga5000 [103]
PV = nRT.......divide both sides by nR
(PV) / (nR) = T
6 0
3 years ago
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