Answer:
50/50 but i don know how a coin toss could determine birth
Hope i helped
Step-by-step explanation:
Answer:A
Step-by-step explanation: A has everthing correct the median is between the numbers 92 98 making it 95 these are the numbers is order 79,86,88,88,92,98,100,106,115,136
60=5k
Is the equation because the word 'is' means equals, so we add an equal sign after the 60. "Five times greater" simply means multiply so we multiply 5 and k.
Then to solve the equation, you would need to divide both sides by 5 to isolate the variable
60/5=5k/5
12=k
I hope this helped!
Answer:
0.35% of students from this school earn scores that satisfy the admission requirement.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
The combined SAT scores for the students at a local high school are normally distributed with a mean of 1479 and a standard deviation of 302.
This means that 
The local college includes a minimum score of 2294 in its admission requirements. What percentage of students from this school earn scores that satisfy the admission requirement?
The proportion is 1 subtracted by the pvalue of Z when X = 2294. So
has a pvalue of 0.9965
1 - 0.9965 = 0.0035
0.0035*100% = 0.35%
0.35% of students from this school earn scores that satisfy the admission requirement.
If Tom throws the dart 30 times, the denominator of the fraction would be 30, as that is the total number, and if he actually hits the target 20 times, that would be the nominator of the fraction as that is the amount out of the total that he hits the target. So if the fraction is 20/30 for the times he hits the target, we can say that 10/30 is the fraction (or probability) that he will miss. We can simplify the fraction by dividing 10 on both sides, getting 1/3. On the bottom the question with the die has 3 scenarios, hit, miss, or neither. it misses when it is 5 or 6, it hits when the die is 1 or 4, and when the die is 2 or 3, nothing happens. as a die has 6 sides, the denominator is 6, and as there is 2 scenarios where you miss the numerator is 2. The fraction or probability for this one, would be 2/6 or 1/3. Using the same math for the following, you can get 1/3 for the die, 1/3 for the first spinner, 1/5 for the first number generator, 1/3 for the second number generator, and 1/3 for the second spinner. As the original part with Tom has a probability of 1/3, we are looking for equal probability, so the correct simulations would then be the die, the first spinner, the second number generator, and the second spinner, while the rest would be incorrect. Hope this helps!<span />
