It is given that, B ≅ BC and AD ≅ CD
We need BD perpendicular to AC, then only we can say triangles AXB and CXB are congruent using the HL theorem.
If BD perpendicular to AC, means that AB and CB are the hypotenuse of triangles AXB and CXB respectively.
from the given information ABCD is a square
If BD and AC bisect each other then AX = CX
Then only we can immediately possible to prove that triangles AXD and CXD are congruent by SSS congruence theorem
Answer:
∠13 ≅ ∠16 - Vertical Angles Theorem
∠10 ≅ ∠14 - corresponding angles for parallel line p and q cut by the transversal s
∠5 ≅ ∠13 - corresponding angles for
parallel lines r and s cut by
the transversal q
∠1 ≅ ∠5 - corresponding angles for
parallel lines r and s cut by
the transversal q
Step-by-step explanation:
Linear Pair Theorem won't be used. When you look at the lines on the image you see that 13 and 16 are vertical from each other making there answer the vertical angles theorem. When you look at 10 and 14 you see that they lie on p and q with s going in the center of them. When you look at 5 and 13 they lie on s and r with q going down the middle of them. With 1 and 5 they also lie on p and q but r goes down the center of them instead of s.
The answer is "alternate exterior angles theorem."
Step-by-step explanation:
2x - 5 = y - 5
2x = y
x = y/2
y - 3 = x + 1
Substitute the value of x here,
y - 3 = 
y - 3 = 
2y - 6 = y + 2
y = 8
Now, x = 8/2
x = 4
So, go for D part, it is the correct answer.
Good Night/Day !
