The payments are ...
A = P(r/n)/(1 -(1+r/n)^(-nt))
where P is the principal amount, $699,000*0.80 = $559,200
r is the annual interest rate, 0.05
n is the number of compoundings per year, 12
t is the number of years.
Then
A = 559,200*(0.05/12)/(1 -(1 +0.05/12)^(-12*35)) = 2822.21
The total of 420 of these payments is $1,185,328.20, which is $626,128.20 more than the loan amount.
Jamie's total finance charge is about $626,128.20.
_____
There is always some minor adustment required in the amount of the last payment. That has not been taken into account here.
Answer:
<u>6x^8y^5</u>
Step-by-step explanation:
3x^2y^4 x 2x^6y
3<em>x</em> x <em>x</em> x <em>y</em> x y x y x y x 2x x x x x x x x x x x x y
6x^8y^5
Answer: 2 19/24 hours was spent in practising.
Step-by-step explanation:
During the first hour, they practiced for 5/8 of an hour. During the second hour, they practiced for 2/3 of an hour. This means that the total time for which they practiced in the first 2 hours would be
5/8 + 2/3 = 31/24 hours
During the last two hours, they first practiced for 3/5 of an hour, took a 1/2 hour break and then practiced the rest of the time. This means that the rest of the time for which they practiced is
2 - (3/5 + 1/2) = 2 - 11/10 = 9/10
Therefore, the time they spent practicing in total would be
31/24 + 3/5 + 9/10 = 67/24 =
2 19/24 hours
Answer:
MN = 160
Step-by-step explanation:
We know that arc MN = arc NO
17g - 10 = 14g+ 20
Subtract 14g from each side
3g -10 = 14g-14g+20
3g -10 =20
Add 10 to each side
3g = 20+10
3g = 30
Divide by 3
3g/3= 30/3
g= 10
We want the arc MN
17g - 10
17(10) - 10
170 -10
160
