Question

What is the slope of a line that is perpendicular to the line whose equation is 2y = 3x - 1?

Answer 1

Answer:

The slope of the line is $-\frac{2}{3}$

Step-by-step explanation:

For any line $y=mx+b$, a line that is perpendicular to it is $y_\perp =-\frac{1}{m} x+b$.

Therefore the slope of the perpendicular line is $-\frac{1}{m}$.

For our case $y=\frac{3}{2}x-\frac{1}{2}$ therefore the slope of the prependicular is the reciprocal of $\frac{3}{2}$ multiplied by $-1.$

$\therefore\:slope=-\frac{2}{3}.$