Question

Calculate the net force on the Fx and Fy of 20 N 17 N 45.50 250

Answer 1

Answer:

$F_{net}$ is 26.25 N

Explanation:

Given that: $F_{x}$ = 20 N, $F_{y}$ = 17 N.

This implies that the two forces are acting at right angle to each other. Thus applying the Pythagoras theorem, we have;

$F_{net}$ = $\sqrt{F_{x} ^{2} + F_{y} ^{2} }$

       = $\sqrt{(20)^{2} + (17)^{2} }$

       = $\sqrt{400 + 289}$

$F_{net}$ = $\sqrt{689}$

      = 26.2488

$F_{net}$ = 26.25 N

The net force is 26.25 N.