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Lilit [14]
3 years ago
9

PLEASE WHAT IS X??? x/3 +4 = 12...

Mathematics
1 answer:
Vladimir79 [104]3 years ago
6 0
X/3 + 4 = 12

First minus 4 on both sides of the equation.

x/3 = 9

Then times 3 on both sides of the equation.

x = 27
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Step-by-step explanation:

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If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalen
MrRissso [65]

Answer:

Option A

Step-by-step explanation:

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Read 2 more answers
URGENT!!!!
babunello [35]

The equation of the hyperbola in standard form is \frac{(y-4)^{2}}{100}-\frac{(x-1)^{2}}{64}=1

Step-by-step explanation:

Let us revise the equation of the hyperbola

The standard form of the equation of a hyperbola with  center (h , k) and transverse axis parallel to the y-axis is  \frac{(y-k)^{2}}{a^{2}}-\frac{(x-h)^{2}}{b^{2}}=1

  • The length of the transverse axis is 2a  
  • The length of the conjugate axis is 2b  

∵ The center of the hyperbola is (1 , 4)

∴ h = 1 and k = 4

∵ The transverse axis is parallel to the y-axis

∴ The form of the equation is  \frac{(y-k)^{2}}{a^{2}}-\frac{(x-h)^{2}}{b^{2}}=1

∴ The length of the transverse axis is 2a  

∵ The length of the transverse axis is 20 units

- Equate 2a by 20 to find a

∴ 2a = 20

- Divide both sides by 2

∴ a = 10

∵ The length of the conjugate axis is 2b

∵ The length of the conjugate axis is 16

- Equate 2b by 16 to find b

∴ 2b = 16

- Divide both sides by 2

∴ b = 8

- Substitute the values of h, k, a, and b in the form of the equation

∴  \frac{(y-4)^{2}}{(10)^{2}}-\frac{(x-1)^{2}}{(8)^{2}}=1

∴  \frac{(y-4)^{2}}{100}-\frac{(x-1)^{2}}{64}=1

The equation of the hyperbola in standard form is \frac{(y-4)^{2}}{100}-\frac{(x-1)^{2}}{64}=1

Learn more:

You can learn more about the hyperbola in brainly.com/question/4054269

#LearnwithBrainly

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Whats 2091 times 1533 ?
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Answer: 3,205,503

Calculator bruh! :)

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